Problem 58
Question
Find polar equations for the circles in Exercises \(57-64 .\) Sketch each circle in the coordinate plane and label it with both its Cartesian and polar equations. $$(x+2)^{2}+y^{2}=4$$
Step-by-Step Solution
Verified Answer
The polar equation of the circle is \(r = -4 \cos \theta\).
1Step 1: Identify the standard form of the circle in Cartesian coordinates
The given equation \((x+2)^2 + y^2 = 4\) is in the standard form of a circle, \((x-h)^2 + (y-k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius. Here, \(h = -2\), \(k = 0\), and \(r = 2\). So, the circle's center is \((-2, 0)\) and its radius is \(2\).
2Step 2: Determine the polar coordinates
In polar coordinates, any point \((x, y)\) has coordinates \((r \cos \theta, r \sin \theta)\). Thus, \(x = r \cos \theta\) and \(y = r \sin \theta\).
3Step 3: Substitute Cartesian coordinates to polar form
Replace \(x\) and \(y\) in the Cartesian equation with their polar equivalents: \((r \cos \theta + 2)^2 + (r \sin \theta)^2 = 4\).
4Step 4: Simplify the polar equation
Expand the equation: \((r \cos \theta + 2)^2 = (r^2 \cos^2 \theta + 4r \cos \theta + 4)\). Then add \(r^2 \sin^2 \theta\) from the \(y^2\) term to get \(r^2 \cos^2 \theta + r^2 \sin^2 \theta + 4r \cos \theta + 4 = 4\).
5Step 5: Use Pythagorean identity
Apply the identity \(\cos^2 \theta + \sin^2 \theta = 1\) to simplify the equation to \(r^2 + 4r \cos \theta + 4 = 4\).
6Step 6: Solve for r in terms of θ
Subtract 4 from both sides: \(r^2 + 4r \cos \theta = 0\). Factor the remaining expression: \(r(r + 4 \cos \theta) = 0\). Thus, \(r = 0\) or \(r = -4 \cos \theta\). Only the latter solution represents the circle beyond the origin.
Key Concepts
Polar CoordinatesCartesian CoordinatesEquation of a CircleConversion Between Coordinate Systems
Polar Coordinates
Polar coordinates provide a unique and fascinating way to represent points on a plane. Unlike Cartesian coordinates, which use a grid-like system of horizontal and vertical axes defined by \(x\) and \(y\), polar coordinates rely on a central point known as the pole (similar to the origin in Cartesian coordinates). In this system, each point is represented by a distance \(r\) from the pole and an angle \(\theta\) from the positive x-axis. This allows us to express any point in the form \( (r, \theta) \).
- \(r\) is the radius or distance from the pole.
- \(\theta\) is the angle measured in radians usually, although degrees can also be used.
Cartesian Coordinates
Cartesian coordinates are the familiar grid system we use to map points on a plane. Named after René Descartes, this system uses a horizontal (x) axis and a vertical (y) axis to locate points. Each point is denoted by \( (x, y) \), where \(x\) represents a point's position along the horizontal axis, and \(y\) indicates its position along the vertical axis.
- The Cartesian system is ideal for linear equations and shapes like lines and rectangles.
- The origin is the point \( (0, 0) \), where the two axes intersect.
Equation of a Circle
An equation of a circle gives us a concise way to describe all the points that make up the circle. In the Cartesian system, the standard form of a circle's equation is \( (x-h)^2 + (y-k)^2 = r^2 \), where:
- \( (h, k) \) is the center of the circle.
- \(r\) is the radius of the circle.
Conversion Between Coordinate Systems
Converting between polar and Cartesian coordinates is a vital skill in mathematics, especially when dealing with problems that involve rotational symmetry or require simpler equations. To convert from Cartesian to polar coordinates, the following relationships are essential:
- \( x = r \cos \theta \) and \( y = r \sin \theta \) help us find the Cartesian coordinates from polar coordinates.
- The formula \( r = \sqrt{x^2 + y^2} \) calculates the distance from the origin to any point.
- \( \theta = \text{atan2}(y, x) \) determines the angle formed with the x-axis.
Other exercises in this chapter
Problem 57
Find the center, foci, vertices, asymptotes, and radius, as appropriate, of the conic sections in Exercises \(57-68 .\) $$ x^{2}+4 x+y^{2}=12 $$
View solution Problem 57
Replace the Cartesian equations in Exercises \(53-66\) with equivalent polar equations. $$x^{2}+y^{2}=4$$
View solution Problem 58
Find the center, foci, vertices, asymptotes, and radius, as appropriate, of the conic sections in Exercises \(57-68 .\) $$ 2 x^{2}+2 y^{2}-28 x+12 y+114=0 $$
View solution Problem 59
Find polar equations for the circles in Exercises \(57-64 .\) Sketch each circle in the coordinate plane and label it with both its Cartesian and polar equation
View solution