Problem 58
Question
Find each product. $$ (2 x-3)^{3} $$
Step-by-Step Solution
Verified Answer
The expansion of \((2x - 3)^{3}\) is \(8x^{3} - 54x^{2} + 162x - 27\).
1Step 1: Understand The Binomial Theorem
The binomial theorem is given as \((a + b)^{n} = a^{n} + \binom{n}{1}a^{n-1}b + \binom{n}{2}a^{n-2}b^{2} + ... + b^{n}\). Here n represents the power, 'a' and 'b' are elements of the binomial. In our problem, a = 2x, b = -3 and n = 3.
2Step 2: Apply The Binomial Theorem
We substitute a = 2x, b=-3 and n=3 in the binomial theorem. So we get \((2x - 3)^{3} = (2x)^{3} + \binom{3}{1}(2x)^{2}*(-3) + \binom{3}{2}(2x)*(-3)^{2} + (-3)^{3}\)
3Step 3: Calculate the binomial coefficients
\binom{3}{1} = 3, \binom{3}{2} = 3. Substitute these values into the equation: \((2x - 3)^{3} = (2x)^{3} + 3*(2x)^{2}*(-3) + 3*(2x)*(-3)^{2} + (-3)^{3}\)
4Step 4: Simplify the expression
Simplify each term to get: \((2x - 3)^{3} = 8x^{3} - 54x^{2} + 162x - 27\)
Key Concepts
Polynomial ExpansionBinomial CoefficientsCubic Expressions
Polynomial Expansion
Polynomial expansion is a straightforward yet powerful technique used in algebra to express a polynomial raised to a power as a sum of terms. Each term in the expansion incorporates coefficients and the elements raised to specific powers. In our original exercise, we aimed to expand the cubic expression \[(2x - 3)^3\]This means we want to expand it into a form that consists of a sum of terms. By doing this, each term will involve powers of both '2x' and '-3'. The polynomial expansion helps to simplify complex polynomial expressions, making them easier to work with in various algebraic operations. To achieve this, we rely on the Binomial Theorem, which acts like a formula for expansion.
Binomial Coefficients
The binomial coefficients are crucial components in the binomial theorem. They are represented in mathematics as \(\binom{n}{k}\), where 'n' is the power and 'k' is the number of the term in the expansion.These coefficients essentially tell us how many ways we can choose 'k' elements from a set of 'n' elements, making them vital for proper expansion. In our exercise:
- We had \(\binom{3}{1} = 3\), indicating three ways to choose 1 item from 3.
- Similarly, \(\binom{3}{2} = 3\) also simplifies to 3, illustrating balance in these selections.
Cubic Expressions
Cubic expressions are polynomials where the highest degree of any variable possesses a power of 3. This is evident in our exercise where we have:\[(2x - 3)^3\]It involves cubing the binomial expression. To handle cubics effectively, the Binomial Theorem simplifies taking cumbersome multiplication into a series of steps with specific coefficients leading to a simplified form.In the step-by-step solution, after correctly applying the formula, we simplified each part of the expression:
- Start by cubing \((2x)^3\) resulting in \(8x^3\).
- The next term was obtained by \(3\times (2x)^2\times (-3)\), simplified to \(-54x^2\).
- The following term simplified from \(3\times (2x)\times(-3)^2\) to \(162x\).
- The last term is \((-3)^3 = -27\).
Other exercises in this chapter
Problem 58
Factor using the formula for the sum or difference of tho cubes. $$ x^{3}+64 $$
View solution Problem 58
Evaluate each expression or indicate that the root is not a real number. $$\sqrt[3]{-125}$$
View solution Problem 58
Add or subtract as indicated. $$\frac{6 x^{2}+17 x-40}{x^{2}+x-20}+\frac{3}{x-4}-\frac{5 x}{x+5}$$
View solution Problem 58
Simplify each exponential expression in Exercises 23–64. $$\frac{10 x^{4} y^{9}}{30 x^{12} y^{-3}}$$
View solution