Problem 58
Question
Factor using the formula for the sum or difference of two cubes. $$x^{3}+64$$
Step-by-Step Solution
Verified Answer
The factorised form of the expression \(x^3 + 64\) using the formula for the sum of cubes is \((x + 4)(x^2 - 4x + 16)\).
1Step 1: Identify A and B
From the expression \(x^3 + 64\), we see that the cube root of \(x^3\) is \(x\) and the cube root of \(64\) is \(4\). Therefore, \(A = x\) and \(B = 4\).
2Step 2: Apply the formula for the sum of cubes
Substitute \(A = x\) and \(B = 4\) into the formula \(A^3 + B^3 = (A + B)(A^2 - AB + B^2)\). This results in \((x + 4)(x^2 - 4x + 16)\).
3Step 3: Check the solution
If the solution is correct, then multiplying the factored form \((x + 4)(x^2 - 4x + 16)\) should return the original expression \(x^3 + 64\). Perform this multiplication to verify your solution.
Other exercises in this chapter
Problem 57
Simplify each exponential expression. $$ \frac{24 x^{3} y^{5}}{32 x^{7} y^{-9}} $$
View solution Problem 58
add or subtract as indicated. $$ \frac{6 x^{2}+17 x-40}{x^{2}+x-20}+\frac{3}{x-4}-\frac{5 x}{x+5} $$
View solution Problem 58
Evaluate each expression in Exercises \(55-66,\) or indicate that the root is not a real number. $$ \sqrt[3]{-125} $$
View solution Problem 58
In Exercises 15–58, find each product. $$ (2 x-3)^{3} $$
View solution