Problem 58
Question
Evaluate the second partial derivatives \(f_{x x^{\prime}} f_{x y^{\prime}} f_{y y^{\prime}}\) and \(f_{y x}\) at the point. $$ f(x, y)=x^{2} e^{y} $$
Step-by-Step Solution
Verified Answer
The second order partial derivatives are: \(f_{xx} = 2e^{y}\), \(f_{xy}=f_{yx} = 2x e^{y}\), \(f_{yy} = x^{2} e^{y}\)
1Step 1: Find the first-order partial derivatives
The first order partial derivatives are found by differentiating the function with respect to one variable while holding the other variable constant. \n- Differentiating with respect to x while holding y constant, we get: \(f_{x} = 2x e^{y}\) \n- Differentiating with respect to y while holding x constant, we get: \(f_{y} = x^{2} e^{y}\)
2Step 2: Find the second-order partial derivatives
The second order partial derivatives are found by differentiating the first order partial derivatives again with respect to the other variable. \n- Differentiating \(f_{x}\) with respect to x while holding y constant, we get: \(f_{xx} = 2e^{y}\) \n- Differentiating \(f_{x}\) with respect to y while holding x constant, we get: \(f_{xy} = 2x e^{y}\) \n- Differentiating \(f_{y}\) with respect to y while holding x constant, we get: \(f_{yy} = x^{2} e^{y}\) \n- Differentiating \(f_{y}\) with respect to x while holding y constant, we get: \(f_{yx} = 2x e^{y}\)
3Step 3: Evaluate the second-order partial derivatives
The second-order partial derivatives don't have any x or y in the function, except for \(f_{xy}\), \(f_{yy}\), and \(f_{yx}\), so their values will remain the same wherever they are.evaluated.
Key Concepts
CalculusMultivariable FunctionsDifferentiationSecond-order Derivatives
Calculus
Calculus is a branch of mathematics that studies continuous change. It helps us understand the behavior of functions and enables us to work out a variety of mathematical problems like those involving rates of change and areas under curves.
Calculus is fundamentally composed of two main concepts:
Calculus is fundamentally composed of two main concepts:
- **Differentiation**: This involves calculating the derivative of a function, which is a measure of how a function changes as its input changes. It's used for finding slopes of curves and solving optimization problems.
- **Integration**: This involves calculating the integral of a function, which is a measure that aggregates values over an interval, like finding the total area under a curve.
Multivariable Functions
Multivariable functions are functions with more than one input variable, forming the base of multivariable calculus. These functions are usually denoted as \(f(x, y, z,...)\).
- These functions are essential in expressing relationships in systems with more than one changing variable.
- The domain of a multivariable function is a subset of \(b{R}^n\), and the range is a subset of \(\bb{R}\).
Differentiation
Differentiation is the process of finding the derivative of a function, which indicates how much the function's output changes in response to changes in its input. In the context of multivariable functions, we use:
- **Partial Differentiation**: This is used to find the rate of change of a multivariable function with respect to one variable, keeping the others constant.
- **Partial derivative with respect to \x\**: \(f_x = \frac{\partial f}{\partial x} = 2x e^y\).
- **Partial derivative with respect to \y\**: \(f_y = \frac{\partial f}{\partial y} = x^2 e^y\).
Second-order Derivatives
Second-order derivatives are simply the derivatives of the first-order derivatives. In the realm of multivariable functions, calculating these provides deeper insights into the function's curvature and interaction between variables.
- **Second-order partial derivatives**: These include derivatives like \(f_{xx},\) \(f_{yy},\) \(f_{xy},\) and \(f_{yx}\).
- **Mixed partial derivatives**: These derivatives, such as \(f_{xy}\) and \(f_{yx},\) are especially interesting because, under certain conditions, they equal each other. This is known as Clairaut's Theorem.
- The second-order derivative with respect to \(x\) is \(f_{xx} = 2e^y\).
- With respect to \(y\), the second-order derivative is \(f_{yy} = x^2 e^y\).
- The mixed derivatives are \(f_{xy} = f_{yx} = 2x e^y\), illustrating the symmetry.
Other exercises in this chapter
Problem 57
Evaluate the second partial derivatives \(f_{x x^{\prime}} f_{x y^{\prime}} f_{y y^{\prime}}\) and \(f_{y x}\) at the point. $$ f(x, y)=\ln (x-y) $$
View solution Problem 57
Sketch the trace of the intersection of each plane with the given sphere. \(x^{2}+y^{2}+z^{2}-4 x-6 y+9=0\) (a) \(x=2\) (b) \(y=3\)
View solution Problem 58
Sketch the trace of the intersection of each plane with the given sphere. \(x^{2}+y^{2}+z^{2}-8 x-6 z+16=0\) (a) \(x=4\) (b) \(z=3\)
View solution Problem 59
A company manufactures two models of bicycles: a mountain bike and a racing bike. The cost function for producing \(x\) mountain bikes and \(y\) racing bikes is
View solution