Problem 58
Question
Describe one similarity and one difference between the graphs of \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) and \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\)
Step-by-Step Solution
Verified Answer
The similarity between the graphs of these two equations is that they both have the same semi-axes lengths, which are 1 and 3. The difference is that the hyperbola defined by \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) opens horizontally, while that defined by \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\) opens vertically.
1Step 1: Identify the orientation of the first equation
For the equation \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\), the 'x' term comes first and is positive, meaning the hyperbola opens along the x-axis (horizontally). The difference in the denominators of the x and y terms signifies the length of the semi-axes a and b, being √9 = 3 and √1=1, respectively.
2Step 2: Identify the orientation of the second equation
In the equation \(\frac{y^{2}}{9}-\frac{x^{2}}{1}=1\), however, the 'y' term comes first and is positive. This means that the hyperbola created from this equation will open along the y-axis (vertically). The lengths of the semi-axes would still be √1 = 1 and √9 =3, respectively.
3Step 3: Formulate the Similarity and Difference
The similarity between these two hyperbolas is that they both have the same length for their semi-axes, which are 1 and 3. The difference, however, is their orientation. The first hyperbola is oriented horizontally while the second one is oriented vertically.
Other exercises in this chapter
Problem 57
Describe how to locate the foci of the graph of \(\frac{x^{2}}{9}-\frac{y^{2}}{1}=1\)
View solution Problem 57
What is a parabola?
View solution Problem 58
Explain how to use \(y^{2}=8 x\) to find the parabola's focus and directrix.
View solution Problem 59
Describe one similarity and one difference between the \(\operatorname{graphs~of~} \frac{x^{2}}{9}-\frac{y^{2}}{1}=1\) and \(\frac{(x-3)^{2}}{9}-\frac{(y+3)^{2}
View solution