Problem 58
Question
Classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. \(x^{2}+y^{2}-4 x-6 y-23=0\)
Step-by-Step Solution
Verified Answer
The equation doesn't represent any of the listed conic sections (circle, parabola, ellipse, or hyperbola) due to a negative term on the right hand side.
1Step 1: Rearrange the equation
First, arrange the equation by grouping the x and y terms together. So it becomes \( (x^{2}-4x)+(y^{2}-6y)=-23 \)
2Step 2: Complete the square for x and y terms
Next, to complete the square, add and subtract square of half of the coefficients of x and y to the equation and rearrange it again, which gives \( (x^{2}-4x+4)+(y^{2}-6y+9)=-23+4+9 \) then simplify this equation to \( (x-2)^{2}+(y-3)^{2}= -10 \)
3Step 3: Finalize the type
Here, \( (x-2)^{2}+(y-3)^{2}= -10 \) cannot describe any of the conic sections where both the x and y terms are squared. Conic sections are always positive, but here we have a negative term on the right hand side.
Key Concepts
CircleParabolaEllipseHyperbola
Circle
A circle is a special type of conic section that is defined as the set of all points in a plane that are equidistant from a given point called the center. The equation of a circle in standard form is \[ (x-h)^2 + (y-k)^2 = r^2 \]where
- \((h, k)\) is the center of the circle, and
- \(r\) is the radius.
Parabola
A parabola is another conic section characterized by a set of points where each point is equidistant from a fixed point, called the focus, and a fixed line, called the directrix. The equation for a parabola can have different forms depending on its orientation.
- If it opens up or down: \[ y = ax^2 + bx + c \]
- If it opens left or right: \[ x = ay^2 + by + c \]
Ellipse
An ellipse is a conic section that looks like a stretched circle. It's the set of all points for which the sum of the distances to two fixed points (foci) is constant. A circle can be considered a special type of ellipse where these foci coincide.The standard form of an ellipse has two variations:
- Horizontal major axis: \[ \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 \]
- Vertical major axis: \[ \frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1 \]
- \((h, k)\) is the center of the ellipse
- \(a\) is the distance from the center to a vertex along the major axis
- \(b\) is the distance from the center to a vertex along the minor axis.
Hyperbola
A hyperbola is a type of conic section derived from a geometric shape capable of exhibiting two symmetrical open curves. Hyperbolas are the set of points for which the absolute difference of their distances to two fixed points (foci) is constant.The standard form of a hyperbola is:
- For horizontal transverse axis: \[ \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \]
- For vertical transverse axis: \[ \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \]
- \((h, k)\) is the center of the hyperbola,
- \(a\) and \(b\) are distances that help define the shape.
Other exercises in this chapter
Problem 57
Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Directrix: \(x=-2\)
View solution Problem 58
Use a graphing utility to graph the curve represented by the parametric equations. Prolate cycloid: \(x=2 \theta-4 \sin \theta, y=2-4 \cos \theta\)
View solution Problem 58
Find the standard form of the equation of the parabola with the given characteristic(s) and vertex at the origin. Directrix: \(x=5\)
View solution Problem 59
Convert the rectangular equation to polar form. Assume \(a
View solution