Problem 58
Question
As part of an annual review of its accounts, a discount brokerage selected a random sample of 36 customers and reviewed the value of their accounts. The mean was 32,000 with a sample standard deviation of 8,200 . What is a \(90 \%\) confidence interval for the mean account value of the population of customers?
Step-by-Step Solution
Verified Answer
The 90% confidence interval for the mean account value is (29,753.16, 34,246.84).
1Step 1: Understand the problem
We want to find the 90% confidence interval for the mean account value of the population of customers. The sample mean is 32,000, the sample standard deviation is 8,200, and the sample size is 36.
2Step 2: Identify the appropriate formula
Since the sample size is large (n = 36), we can use the formula for the confidence interval of the mean using the z-distribution: \[CI = \bar{x} \pm z \times \frac{\sigma}{\sqrt{n}}\]where \(\bar{x}\) is the sample mean, \(\sigma\) is the sample standard deviation, and \(n\) is the sample size. The z-score for a 90% confidence interval is approximately 1.645.
3Step 3: Calculate the standard error
The standard error of the mean (SEM) is given by \(\frac{\sigma}{\sqrt{n}}\). Substitute into the formula:\[SEM = \frac{8,200}{\sqrt{36}} = \frac{8,200}{6} = 1,366.67\]
4Step 4: Find the margin of error
The margin of error (ME) is calculated using the z-score and the standard error:\[ ME = z \times SEM = 1.645 \times 1,366.67 = 2,246.84 \]
5Step 5: Calculate the confidence interval
The confidence interval is found by subtracting and adding the margin of error from the sample mean:\[CI = 32,000 \pm 2,246.84\]So, the confidence interval will be: \[(32,000 - 2,246.84, 32,000 + 2,246.84) = (29,753.16, 34,246.84)\]
Key Concepts
Sample MeanStandard Error of the MeanMargin of Error
Sample Mean
The sample mean is a basic concept in statistics, representing the average value of a sample set. In the context of our exercise, the sample mean is the average account value found in a sample of 36 customers. Here, the sample mean is recorded as 32,000.
- The sample mean is calculated by summing up all the individual data points (account values in this case) and then dividing the total by the number of data points (customers) in the sample.
- The formula for the sample mean is given by: \( \bar{x} = \frac{\sum x_i}{n} \), where \( x_i \) is each individual data point, and \( n \) is the total number of data points.
Standard Error of the Mean
The Standard Error of the Mean (SEM) indicates how much the sample mean is expected to vary if we took multiple samples from the population. It provides insight into the precision of the sample mean as an estimate of the population mean. In our example, the SEM is calculated as 1,366.67.
- SEM is found by dividing the sample standard deviation by the square root of the sample size.
- The formula is: \( SEM = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the sample standard deviation, and \( n \) is the sample size.
Margin of Error
The margin of error quantifies the uncertainty or potential error in the estimate of the population mean. It's the amount added and subtracted from the sample mean to create the confidence interval. For our exercise, the margin of error is 2,246.84.
- The margin of error depends on the desired confidence level (here, 90%) and the standard error.
- It is calculated by multiplying the z-score corresponding to the desired confidence level by the SEM: \( ME = z \times SEM \).
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