Problem 58
Question
A glass vial containing a 16.0 -g sample of an enzyme is cooled in an ice bath. The bath contains water and 0.120 \(\mathrm{kg}\) of ice. The sample has specific heat 2250 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K}\) ; the glass vial has mass 6.00 \(\mathrm{g}\) and specific heat 2800 \(\mathrm{J} / \mathrm{kg} \cdot \mathrm{K} .\) How much ice melts in cooling the enzyme sample from room temperature \(\left(19.5^{\circ} \mathrm{C}\right)\) to the temperature of the ice bath?
Step-by-Step Solution
Verified Answer
Approximately 3.08 g of ice melts.
1Step 1: Calculate Heat Lost by Enzyme
The heat lost by the enzyme can be calculated using the formula: \[ Q = m imes c imes \Delta T \]where \( m = 0.016 \) kg (mass of the enzyme), \( c = 2250 \) J/kg·K (specific heat of the enzyme), and \( \Delta T = 19.5 \) K (change in temperature from 19.5°C to 0°C). Substituting the values, we get: \[ Q_{enzyme} = 0.016 \times 2250 \times 19.5 = 702 \, \text{J} \]
2Step 2: Calculate Heat Lost by Glass Vial
Similarly, calculate the heat lost by the glass vial:\[ Q = m \times c \times \Delta T \]where \( m = 0.006 \) kg (mass of the glass), \( c = 2800 \) J/kg·K (specific heat of the glass), and \( \Delta T = 19.5 \) K. Substituting the values, we get: \[ Q_{glass} = 0.006 \times 2800 \times 19.5 = 327.6 \, \text{J} \]
3Step 3: Total Heat Lost by System
The total heat lost by the system (enzyme and glass vial) is the sum of the heat lost by each component:\[ Q_{total} = Q_{enzyme} + Q_{glass} = 702 + 327.6 = 1029.6 \, \text{J} \]
4Step 4: Calculate Mass of Ice Melted
The heat required to melt ice is given by the latent heat equation:\[ Q = m \times L_f \]where \( m \) is the mass of the ice melted and \( L_f = 334,000 \) J/kg is the latent heat of fusion for ice. Setting the total heat lost equal to the heat required to melt the ice, we get:\[ 1029.6 = m \times 334,000 \]Solve for \( m \) to find the mass of ice melted:\[ m = \frac{1029.6}{334,000} \approx 0.00308 \text{ kg} \] or 3.08 g.
Key Concepts
Specific Heat CapacityLatent Heat of FusionHeat Transfer
Specific Heat Capacity
Specific heat capacity is an essential principle in thermodynamics. It's a measure of the amount of heat energy required to change the temperature of a substance by one degree.
In simple terms, it tells us how easily a substance can change its temperature. This quality depends on the substance's composition and its current state.
If a substance has a high specific heat capacity, it can absorb more heat before its temperature rises. This makes it ideal for regulating temperatures in various applications.To calculate it, we use the formula:
In simple terms, it tells us how easily a substance can change its temperature. This quality depends on the substance's composition and its current state.
If a substance has a high specific heat capacity, it can absorb more heat before its temperature rises. This makes it ideal for regulating temperatures in various applications.To calculate it, we use the formula:
- \( Q = m \times c \times \Delta T \)
- \( Q \) is the heat absorbed or released,
- \( m \) is the mass of the sample,
- \( c \) is specific heat capacity, and
- \( \Delta T \) is the change in temperature.
Latent Heat of Fusion
The latent heat of fusion is another core concept in thermodynamics. When a substance changes its state, such as from solid to liquid, it requires a specified amount of energy.
This energy change happens at a constant temperature and without changing the temperature of the substance.
The energy required for such a phase change is referred to as latent heat.The latent heat of fusion specifically refers to the energy needed to convert a solid into a liquid. For ice, this conversion requires 334,000 J/kg. Using the formula:
This energy change happens at a constant temperature and without changing the temperature of the substance.
The energy required for such a phase change is referred to as latent heat.The latent heat of fusion specifically refers to the energy needed to convert a solid into a liquid. For ice, this conversion requires 334,000 J/kg. Using the formula:
- \( Q = m \times L_f \)
- \( Q \) is the heat energy,
- \( m \) is the mass of the solid or liquid changing state,
- \( L_f \) is the latent heat of fusion.
Heat Transfer
Heat transfer is a fundamental concept in thermodynamics, detailing the movement of heat energy between different substances.
Heat energy naturally flows from a hotter object to a colder one until thermal equilibrium is reached.
There are three major methods of heat transfer:
Heat energy naturally flows from a hotter object to a colder one until thermal equilibrium is reached.
There are three major methods of heat transfer:
- Conduction: Direct transfer of heat through contact between substances.
- Convection: Transfer of heat through fluid movements, such as in liquids or gases.
- Radiation: Transfer of heat through electromagnetic waves, without needing a medium.
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