Problem 58
Question
A cylindrical hoop, a cylinder, and a sphere of equal radius and mass are released at the same time from the top of an inclined plane. Using the conservation of mechanical energy, show that the sphere always gets to the bottom of the incline first with the fastest speed and that the hoop always arrives last with the slowest speed.
Step-by-Step Solution
Verified Answer
The sphere reaches the bottom first, followed by the cylinder, and finally the hoop because their velocities are in the order: sphere > cylinder > hoop.
1Step 1: Understand the Problem
We have three objects: a cylindrical hoop, a cylinder, and a sphere. They have equal radius and mass, and are released from the same height on an inclined plane. We need to show that due to conservation of energy, the sphere reaches the bottom first, and the hoop reaches last.
2Step 2: Conservation of Mechanical Energy
For each object, apply the conservation of mechanical energy. The total mechanical energy at the top (potential energy) is converted to kinetic energy (translational + rotational) at the bottom:\[ mgh = \frac{1}{2} mv^2 + \frac{1}{2} I \omega^2 \]where \( m \) is the mass, \( g \) is the gravitational acceleration, \( h \) is the height of the incline, \( v \) is the linear velocity, \( I \) is the moment of inertia, and \( \omega \) is the angular velocity (\( \omega = \frac{v}{r} \), \( r \) is the radius).
3Step 3: Calculate Moment of Inertia for Each Object
Moment of inertia is different for each object:- Hoop: \( I = mr^2 \)- Cylinder: \( I = \frac{1}{2}mr^2 \)- Sphere: \( I = \frac{2}{5}mr^2 \)
4Step 4: Substitute Moment of Inertia into Energy Equation
Substitute the moment of inertia values into the energy equations for each object:- Hoop: \[ mgh = \frac{1}{2} mv^2 + \frac{1}{2} (mr^2) \left(\frac{v}{r}\right)^2 = mv^2 \]- Cylinder: \[ mgh = \frac{1}{2} mv^2 + \frac{1}{2} \left(\frac{1}{2}mr^2\right) \left(\frac{v}{r}\right)^2 = \frac{3}{4}mv^2 \]- Sphere: \[ mgh = \frac{1}{2} mv^2 + \frac{1}{2} \left(\frac{2}{5}mr^2\right) \left(\frac{v}{r}\right)^2 = \frac{7}{10}mv^2 \]
5Step 5: Solve for Velocity v
Solve each equation for \( v \):- Hoop: \[ v = \sqrt{gh} \]- Cylinder: \[ v = \sqrt{\frac{4gh}{3}} \]- Sphere: \[ v = \sqrt{\frac{10gh}{7}} \]
6Step 6: Compare Velocities
Compare the magnitudes:- For the hoop: \( v = \sqrt{gh} \)- For the cylinder: \( v = \sqrt{\frac{4gh}{3}} \)- For the sphere: \( v = \sqrt{\frac{10gh}{7}} \)Since \( \sqrt{\frac{10}{7}} > \sqrt{\frac{4}{3}} > 1 \), the sphere reaches fastest.
Key Concepts
Moment of InertiaRotational MotionConservation of EnergyInclined Plane
Moment of Inertia
The moment of inertia is a crucial concept in understanding rotational motion. It is a measure of an object's resistance to changes in its rotational motion. The formula for moment of inertia varies depending on the shape and mass distribution of the object.
For instance:
For instance:
- **Cylindrical Hoop:** Its moment of inertia is calculated as \( I = mr^2 \). This means the mass is concentrated farther from the axis of rotation, providing higher inertia.
- **Cylinder:** The formula here is \( I = \frac{1}{2}mr^2 \), indicating that the mass is distributed more evenly around the axis.
- **Sphere:** It has \( I = \frac{2}{5}mr^2 \), which signifies that it has the smallest moment of inertia among the three, allowing it to accelerate faster in rotational motion.
Rotational Motion
Rotational motion describes an object rotating around an axis. When objects roll down an incline, they simultaneously move linearly and rotate. The speed of this motion depends on both linear velocity and angular velocity.
The relationship between the two is given by \( \omega = \frac{v}{r} \), where \( \omega \) is the angular velocity, \( v \) is the linear velocity, and \( r \) is the radius of the object.
The kinetic energy of rotating objects is the sum of translational kinetic energy \( \left( \frac{1}{2}mv^2 \right) \) and rotational kinetic energy \( \left( \frac{1}{2}I\omega^2 \right) \).
The relationship between the two is given by \( \omega = \frac{v}{r} \), where \( \omega \) is the angular velocity, \( v \) is the linear velocity, and \( r \) is the radius of the object.
The kinetic energy of rotating objects is the sum of translational kinetic energy \( \left( \frac{1}{2}mv^2 \right) \) and rotational kinetic energy \( \left( \frac{1}{2}I\omega^2 \right) \).
- Hoop: More energy is used in rotational motion due to higher inertia, resulting in a slower descent.
- Cylinder: Balanced energy distribution between linear and rotational motion.
- Sphere: Least rotational inertia leads to faster linear acceleration.
Conservation of Energy
The principle of conservation of energy states that energy in a closed system remains constant. For our inclined plane scenario, potential energy is converted to kinetic energy as objects roll down.
The energy equation is \( mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 \), indicating that all potential energy \( mgh \) at the start transforms into kinetic energy at the bottom of the incline.
Different forms of kinetic energy are affected by inertia:
The energy equation is \( mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2 \), indicating that all potential energy \( mgh \) at the start transforms into kinetic energy at the bottom of the incline.
Different forms of kinetic energy are affected by inertia:
- **Hoop:** Its higher inertia means more energy goes into rotation, reducing its speed.
- **Cylinder:** A fair split between rotational and linear energy, making it moderately fast.
- **Sphere:** The smallest moment of inertia allows more energy for linear motion, increasing speed.
Inclined Plane
An inclined plane is a simple physics concept used to analyze forces and motion. In this context, it's a flat surface tilted at an angle, causing objects to experience gravitational force components along the plane.
As objects descend the plane under gravity, their potential energy \( mgh \) is converted to kinetic energy.
The angle and friction do not change among the objects here, making inertia the main differentiator. However:
As objects descend the plane under gravity, their potential energy \( mgh \) is converted to kinetic energy.
The angle and friction do not change among the objects here, making inertia the main differentiator. However:
- Smoother planes, or less friction, allow faster speeds.
- A steeper incline increases the component of gravitational force along the plane, speeding up descent for all objects.
Other exercises in this chapter
Problem 56
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