Problem 57
Question
Write the general form of the equation of the line that passes through the points. $$(3,2),(0,-1)$$
Step-by-Step Solution
Verified Answer
The general form of the line passing through the points \((3,2)\) and \((0,-1)\) is \(y = x - 1\).
1Step 1: Determine the Slope
To find the slope \((m)\) of the line connecting the points \((x_1, y_1)\) and \((x_2, y_2)\), use the equation: \(m = \frac{y_2 - y_1} {x_2 - x_1}\), this gives \(m = \frac{-1-2}{0-3} = 1\).
2Step 2: Calculate the Y-Intercept
Knowing the slope \(m\), calculate the Y-intercept \((b)\) using the equation: \(b = y_1 - m * x_1\) with the values \((x_1, y_1)\) as \((3,2)\). This gives: \(b = 2 - 1*3 = -1\).
3Step 3: Write the Linear Equation
The line's general equation is expressed in slope-intercept form as \(y = mx + b\). With \(m = 1\) and \(b = -1\), the equation becomes: \(y = x - 1\).
Key Concepts
Slope CalculationY-InterceptSlope-Intercept Form
Slope Calculation
Understanding the slope of a line is crucial as it describes the line's steepness and direction. To calculate the slope, often represented by the symbol m, we use two points that lie on the line. The formula for slope is
\( m = \frac{y_2 - y_1}{x_2 - x_1} \).
For example, if we're given the points
\((3, 2)\) and \((0, -1)\), we subtract the y-coordinate of the first point from the second, and do the same for the x-coordinates:
\( m = \frac{-1 - 2}{0 - 3} \), which simplifies to
\( m = \frac{-3}{-3} = 1 \).
The slope here is 1, indicating that for every unit the line moves horizontally, it also moves up by the same amount vertically. Remember, a negative slope means the line is going downwards as it moves from left to right, while a slope of zero means the line is horizontal.
\( m = \frac{y_2 - y_1}{x_2 - x_1} \).
For example, if we're given the points
\((3, 2)\) and \((0, -1)\), we subtract the y-coordinate of the first point from the second, and do the same for the x-coordinates:
\( m = \frac{-1 - 2}{0 - 3} \), which simplifies to
\( m = \frac{-3}{-3} = 1 \).
The slope here is 1, indicating that for every unit the line moves horizontally, it also moves up by the same amount vertically. Remember, a negative slope means the line is going downwards as it moves from left to right, while a slope of zero means the line is horizontal.
Y-Intercept
The y-intercept of a line is the point where it crosses the y-axis. This value is signified by the letter b in equations. Once we've calculated the slope, we can find the y-intercept using another point on the line and the formula
\( b = y - m \cdot x \),
where x and y are the coordinates of the known point, and m is the slope. Using the earlier example with the slope of 1 and the point
\((3, 2)\), we insert these into the equation:
\( b = 2 - (1 \cdot 3) = -1 \).
This calculation tells us that the line crosses the y-axis at -1.
\( b = y - m \cdot x \),
where x and y are the coordinates of the known point, and m is the slope. Using the earlier example with the slope of 1 and the point
\((3, 2)\), we insert these into the equation:
\( b = 2 - (1 \cdot 3) = -1 \).
This calculation tells us that the line crosses the y-axis at -1.
- If b is positive, the line crosses the y-axis above the origin.
- If b is negative, it crosses below the origin.
- If b is zero, the line goes through the origin.
Slope-Intercept Form
The slope-intercept form of a linear equation provides a quick way to graph a line and is written as
\( y = mx + b \),
where m is the slope and b is the y-intercept. It's called 'slope-intercept form' because it directly shows both the slope and the y-intercept, which are key to understanding the line's behavior. From our calculations with slope m=1 and y-intercept b=-1, the slope-intercept form of the line is
\( y = x - 1 \).
The beauty of this form is that it's straightforward to plot: start at the y-intercept on the y-axis, and from that point, use the slope to find other points on the line. For instance, since our slope here is 1 (or
\( \frac{1}{1} \)), we move 1 unit up and 1 unit to the right to find another point, then draw the line through these points.
\( y = mx + b \),
where m is the slope and b is the y-intercept. It's called 'slope-intercept form' because it directly shows both the slope and the y-intercept, which are key to understanding the line's behavior. From our calculations with slope m=1 and y-intercept b=-1, the slope-intercept form of the line is
\( y = x - 1 \).
The beauty of this form is that it's straightforward to plot: start at the y-intercept on the y-axis, and from that point, use the slope to find other points on the line. For instance, since our slope here is 1 (or
\( \frac{1}{1} \)), we move 1 unit up and 1 unit to the right to find another point, then draw the line through these points.
Other exercises in this chapter
Problem 56
Find two quadratic functions, one that opens upward and one that opens downward, whose graphs have the given \(x\) -intercepts. (There are many correct answers.
View solution Problem 56
Find all the real zeros of the polynomial function. Determine the multiplicity of each zero. Use a graphing utility to verify your results. \(f(x)=x^{4}-x^{3}-2
View solution Problem 57
Write the polynomial (a) as the product of factors that are irreducible over the rationals, (b) as the product of linear and quadratic factors that are irreduci
View solution Problem 57
Find two quadratic functions, one that opens upward and one that opens downward, whose graphs have the given \(x\) -intercepts. (There are many correct answers.
View solution