Problem 57
Question
Write a balanced equation for the reaction of hydrogen gas with bromine gas.
Step-by-Step Solution
Verified Answer
The balanced chemical equation for the reaction is: H2 + Br2 -> 2HBr.
1Step 1: Identify Reactants
Identify the chemical formulas of the reactants involved. Hydrogen gas is represented as H2 and bromine gas as Br2.
2Step 2: Write the Unbalanced Equation
Write the unbalanced chemical equation with the reactants on the left side and the products on the right side. The product of hydrogen gas reacting with bromine gas is hydrogen bromide (HBr). The unbalanced equation thus is: H2 + Br2 -> HBr.
3Step 3: Balance the Equation
Balance the number of atoms on both sides of the equation. To balance the hydrogen atoms, place a coefficient of 2 in front of the product HBr. The bromine atoms are then balanced by placing a coefficient of 2 in front of the HBr. The balanced chemical equation is: H2 + Br2 -> 2HBr.
Key Concepts
Chemical ReactionsStoichiometryChemical Formulas
Chemical Reactions
Chemical reactions are fundamental processes where reactants transform into products. Imagine you’re in a dance, and dancers switch partners; that’s similar to how atoms in reactants rearrange to form new compounds. For this transformation to be complete, the reaction must be balanced, meaning the same number of each type of atom must exist on both sides of the equation.
Understanding chemical reactions involves recognizing reactant and product molecules, predicting the possible outcome of the reaction, and then confirming if energy is absorbed or released. For instance, when hydrogen gas ( (H_2)) reacts with bromine gas ( (Br_2)), they form hydrogen bromide ( (HBr)). This is a synthesis reaction, where two or more substances combine to form a more complex product.
Understanding chemical reactions involves recognizing reactant and product molecules, predicting the possible outcome of the reaction, and then confirming if energy is absorbed or released. For instance, when hydrogen gas ( (H_2)) reacts with bromine gas ( (Br_2)), they form hydrogen bromide ( (HBr)). This is a synthesis reaction, where two or more substances combine to form a more complex product.
Stoichiometry
Stoichiometry is the math behind chemistry. It's like a chef's recipe, where the quantity of each ingredient must be measured accurately to get the desired final dish. In terms of chemistry, stoichiometry allows us to calculate the amounts of reactants and products involved in a chemical reaction. It ensures that the law of conservation of mass is followed: the mass of reactants should equal the mass of the products.
To apply stoichiometry, one begins with a balanced chemical equation, just like the one provided in the solution: (H_2 + Br_2 -> 2HBr). This equation tells us that one molecule of hydrogen gas and one molecule of bromine gas react to form two molecules of hydrogen bromide. Using stoichiometry, we can determine how much of each reactant is needed and what amount of product can be expected from the reaction.
To apply stoichiometry, one begins with a balanced chemical equation, just like the one provided in the solution: (H_2 + Br_2 -> 2HBr). This equation tells us that one molecule of hydrogen gas and one molecule of bromine gas react to form two molecules of hydrogen bromide. Using stoichiometry, we can determine how much of each reactant is needed and what amount of product can be expected from the reaction.
Chemical Formulas
Chemical formulas are shorthand representations of molecules and compounds, much like initials are used for names. They tell us the type and number of atoms in a molecule. For instance, for hydrogen gas, the chemical formula is (H_2), indicating that two hydrogen atoms bond together. Similarly, bromine gas is denoted as (Br_2), representing a diatomic molecule consisting of two bromine atoms.
When balancing chemical equations, it’s crucial to pay attention to these formulas because they guide us in maintaining the same number of each type of atom on both sides of the equation. With this knowledge, the equation from the exercise was balanced by analyzing the chemical formula of hydrogen bromide ( (HBr)), understanding that it consists of one hydrogen atom and one bromine atom, and then using coefficients to match the atom counts on both sides of the reaction.
When balancing chemical equations, it’s crucial to pay attention to these formulas because they guide us in maintaining the same number of each type of atom on both sides of the equation. With this knowledge, the equation from the exercise was balanced by analyzing the chemical formula of hydrogen bromide ( (HBr)), understanding that it consists of one hydrogen atom and one bromine atom, and then using coefficients to match the atom counts on both sides of the reaction.
Other exercises in this chapter
Problem 55
Write a balanced chemical equation for the reaction of solid lithium with liquid water.
View solution Problem 56
Write a balanced chemical equation for the reaction of solid potassium with liquid water.
View solution Problem 58
Write a balanced equation for the reaction of chlorine gas with fluorine gas.
View solution Problem 59
The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane \(\left(\mathrm{C}_{8} \mathrm{H}_{18}\right)\) and calculate th
View solution