Problem 57
Question
Use an algebraic approach to solve each problem. If the complement of an angle is \(5^{\circ}\) less than one-sixth of its supplement, find the measure of the angle.
Step-by-Step Solution
Verified Answer
The angle measures \(78^{\circ}\).
1Step 1: Define the Unknowns
Let the angle be denoted as \(x\). The complement of an angle is \(90^{\circ} - x\), and the supplement of an angle is \(180^{\circ} - x\).
2Step 2: Express the Problem Statement Algebraically
According to the problem, the complement of the angle \((90^{\circ} - x)\) is equal to \(5^{\circ}\) less than one-sixth of its supplement \(\left(\frac{1}{6}(180^{\circ} - x) - 5^{\circ}\right)\).
3Step 3: Set Up the Equation
We can set up the equation based on step 2: \[90 - x = \frac{1}{6}(180 - x) - 5\]
4Step 4: Simplify the Equation
The equation becomes: \[90 - x = 30 - \frac{x}{6} - 5\]Simplify the right-hand side: \[90 - x = 25 - \frac{x}{6}\]
5Step 5: Eliminate the Fraction
Multiply every term by 6 to eliminate the fraction: \[6(90 - x) = 6\left(25 - \frac{x}{6}\right)\]This results in: \[540 - 6x = 150 - x\]
6Step 6: Solve for \(x\)
Isolate \(x\) by solving the equation:\[540 - 150 = 6x - x\]\[390 = 5x\]Divide both sides by 5:\[x = 78\]
7Step 7: Verify the Solution
The angle is \(78^{\circ}\).The complement is \(90 - 78 = 12^{\circ}\).The supplement is \(180 - 78 = 102^{\circ}\).One-sixth of the supplement is \(\frac{1}{6} \times 102 = 17^{\circ}\).\(17^{\circ} - 5^{\circ} = 12^{\circ}\), which matches the complement.
Key Concepts
Complementary AnglesSupplementary AnglesEquation Solving
Complementary Angles
Complementary angles are a pair of angles whose measures add up to precisely 90 degrees. This can happen in various geometric settings, such as when two angles form a right angle with a common side. It’s crucial to remember this specific sum because it often comes into play in different geometry and trigonometry problems.
To understand it better, think of a right angle as a complete 90-degree turn. If you know one angle and need to find its complement, simply subtract the known angle from 90 degrees. For example, if one angle measures 30 degrees, then the complement is 90 - 30 = 60 degrees.
To understand it better, think of a right angle as a complete 90-degree turn. If you know one angle and need to find its complement, simply subtract the known angle from 90 degrees. For example, if one angle measures 30 degrees, then the complement is 90 - 30 = 60 degrees.
- Helpful rule: Complementary angles always sum to 90 degrees.
- Used heavily in exercises involving right angles.
- Knowing the measure of one angle helps calculate the other easily.
Supplementary Angles
Supplementary angles are two angles whose measures add up to 180 degrees. They are typically found when angles are around a straight line, creating what is known as a linear pair. Like complementary angles, they are fundamental in understanding relationships between angles in various geometrical figures.
To find the supplement of an angle, subtract the given angle from 180 degrees. For instance, if one angle measures 110 degrees, the supplementary angle would be 180 - 110 = 70 degrees.
To find the supplement of an angle, subtract the given angle from 180 degrees. For instance, if one angle measures 110 degrees, the supplementary angle would be 180 - 110 = 70 degrees.
- Main point: Supplementary angles always sum to 180 degrees.
- Commonly appear in problems with straight lines or linear pairs.
- Finding one angle can immediately lead you to the supplement.
Equation Solving
Equation solving involves finding the unknown value or values that satisfy an equation. This process can often involve several steps like setting up an equation based on given conditions, simplifying it, and methodically isolating the variable.
To effectively solve an equation:
To effectively solve an equation:
- Identify and define unknowns clearly.
- Set up the equation based on the problem's given conditions.
- Simplify the equation, if needed, to make it easier to solve.
- Isolate the unknown variable, often by performing inverse operations.
- Always verify the solution by plugging it back into the original equation to ensure correctness.
Other exercises in this chapter
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