Problem 57
Question
The distillation of phenol with zinc dust gives (a) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{C}_{6} \mathrm{H}_{5}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OC}_{6} \mathrm{H}_{5}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{6}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{12}\)
Step-by-Step Solution
Verified Answer
The product is benzene, \( \mathrm{C}_6\mathrm{H}_6 \).
1Step 1: Understanding the Reaction
Phenol is represented by the chemical formula \( \mathrm{C}_6\mathrm{H}_5\mathrm{OH} \). When phenol is heated with zinc dust, a reduction reaction occurs, which removes the oxygen attached to the phenol, effectively reducing the phenol to its simpler hydrocarbon form.
2Step 2: Identify the Reaction Type
The reaction of phenol with zinc dust is a type of reduction reaction. Zinc serves as the reducing agent, which helps remove the oxygen atom from the phenol molecule, leading to the formation of benzene, \( \mathrm{C}_6\mathrm{H}_6 \).
3Step 3: Predict the Reaction Product
In this reaction, zinc dust reduces phenol to benzene by removing the oxygen atom in the form of zinc oxide. This means the expected product of phenol distillation with zinc dust is benzene \( \mathrm{C}_6\mathrm{H}_6 \).
Key Concepts
zinc dust reductionbenzene formationorganic chemistry reactions
zinc dust reduction
Zinc dust reduction is a popular technique in organic chemistry, used to convert phenolic compounds into hydrocarbons. This reduction process involves zinc dust as a reducing agent. When phenol
Zinc itself, acting as a reducing agent, donates electrons to phenol. Often, students find it helpful to think of zinc as a helper that strips away the oxygen by forming zinc oxide \( (\mathrm{ZnO}) \) with this element, leaving behind pure hydrocarbons. This process emphasizes the versatile use of metal dust in chemistry, being an effective reductant even in seemingly stable molecules like phenol.
Overall, mastering zinc dust reduction opens doors to understanding more about hydrocarbon synthetization and reaction mechanisms in organic chemistry.
- has the chemical structure of \( \mathrm{C}_6\mathrm{H}_5\mathrm{OH} \)
- is heated in the presence of zinc dust
Zinc itself, acting as a reducing agent, donates electrons to phenol. Often, students find it helpful to think of zinc as a helper that strips away the oxygen by forming zinc oxide \( (\mathrm{ZnO}) \) with this element, leaving behind pure hydrocarbons. This process emphasizes the versatile use of metal dust in chemistry, being an effective reductant even in seemingly stable molecules like phenol.
Overall, mastering zinc dust reduction opens doors to understanding more about hydrocarbon synthetization and reaction mechanisms in organic chemistry.
benzene formation
Benzene formation from phenol through zinc dust reduction is a fundamental concept in organic chemistry. Benzene is a simple aromatic hydrocarbon with the formula \( \mathrm{C}_6\mathrm{H}_6 \), characterized by its ring structure with alternating double and single bonds, creating a stable resonance system.
In this reaction, phenol's hydroxyl group (\( \mathrm{OH} \)) is detached, leading to the reformation of the benzene ring.
This reaction underscores the importance of benzene in chemistry due to its foundation for more complex aromatic structures. Understanding benzene formation helps chemists deduce subsequent reaction pathways in complex organic syntheses, making it an essential part of the organic chemistry toolkit.
In this reaction, phenol's hydroxyl group (\( \mathrm{OH} \)) is detached, leading to the reformation of the benzene ring.
- This reaction removes just the oxygen atom.
- It ensures no other substitutions or structural changes in the carbon framework.
This reaction underscores the importance of benzene in chemistry due to its foundation for more complex aromatic structures. Understanding benzene formation helps chemists deduce subsequent reaction pathways in complex organic syntheses, making it an essential part of the organic chemistry toolkit.
organic chemistry reactions
Organic chemistry reactions are a diverse and vast field, encompassing different mechanisms and transformations like addition, substitution, and reduction. The reduction of phenol to benzene is a classic example of how selective elimination of certain atoms and groups can yield a different product entirely.
Reduction reactions involve the gain of electrons, often facilitated by reducing agents like zinc. In zinc dust reduction, the goal is to simplify a molecule, retaining only the core hydrocarbon structure.
The study of these reactions not only enhances comprehension of chemical processes but also equips students with the knowledge to approach real-world problems via organic synthesis methods. A thorough grasp of reactions like zinc dust reduction is crucial for organic synthesis, pharmaceutical development, and chemical engineering solutions.
Reduction reactions involve the gain of electrons, often facilitated by reducing agents like zinc. In zinc dust reduction, the goal is to simplify a molecule, retaining only the core hydrocarbon structure.
- Phenolic compounds serve as excellent models for studying these transformations.
- The reaction highlights how complex molecules can be broken down in a controlled manner.
The study of these reactions not only enhances comprehension of chemical processes but also equips students with the knowledge to approach real-world problems via organic synthesis methods. A thorough grasp of reactions like zinc dust reduction is crucial for organic synthesis, pharmaceutical development, and chemical engineering solutions.
Other exercises in this chapter
Problem 55
Ethylene reacts with \(1 \%\) cold alkaline \(\mathrm{KMnO}_{4}\) to form (a) ethylene glycol (b) oxalic acid (c) HCHO (d) ethyl alcohol
View solution Problem 56
The reaction of \(\mathrm{CO}_{2}\) with sodium phenoxide at \(400 \mathrm{~K}\) results in the formation of (a) salicyaldehdye (b) sodium benzoate (c) benzoic
View solution Problem 58
When diethyl ether is treated with an excess of \(\mathrm{Cl}_{2}\) in the presence of sunlight, the product formed is (a) \(\mathrm{CH}_{3} \mathrm{CHCl}-\math
View solution Problem 59
The ionization constant of phenol is higher than that of ethanol because (a) phenoxide ion is a stronger base than ethoxide ion (b) phenoxide ion is stabilized
View solution