Problem 57
Question
Suppose that $$ A=\left[\begin{array}{ll} 2 & 4 \\ 3 & 6 \end{array}\right] $$ (a) Compute det \(A\). Is \(A\) invertible?
Step-by-Step Solution
Verified Answer
The determinant of matrix \( A \) is 0, so \( A \) is not invertible.
1Step 1: Understand the Determinant Formula for 2x2 Matrix
The determinant of a 2x2 matrix \( A = \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \) is calculated using the formula: \( \text{det}(A) = ad - bc \). We will use this formula to find the determinant of matrix \( A \) given in the problem.
2Step 2: Identify Elements of the Matrix
For the given matrix \( A = \left[ \begin{array}{cc} 2 & 4 \ 3 & 6 \end{array} \right] \), assign each element according to the formula: \( a = 2 \), \( b = 4 \), \( c = 3 \), and \( d = 6 \).
3Step 3: Compute the Determinant
Substitute the identified elements into the determinant formula: \( \text{det}(A) = (2)(6) - (4)(3) \). Calculate each product to get \( 12 - 12 \). Thus, \( \text{det}(A) = 0 \).
4Step 4: Determine Invertibility
A matrix is invertible if and only if its determinant is non-zero. Since \( \text{det}(A) = 0 \), matrix \( A \) is not invertible.
Key Concepts
2x2 matrixmatrix invertibilitydeterminant formula
2x2 matrix
A 2x2 matrix is a simple form of a matrix that consists of two rows and two columns. It is one of the most fundamental topics in linear algebra. In a 2x2 matrix, each position within the matrix can be identified using a combination of row and column indices, such as the first row, first column, usually written as \( a_{11} \), etc.
Here’s how to think about a 2x2 matrix:
In this form, \( a \), \( b \), \( c \), and \( d \) are numbers or expressions in the matrix's individual cells. These numbers can be whole numbers, fractions, or even variables, depending on how it's used in a problem or application.
Here’s how to think about a 2x2 matrix:
- The top row is designated as the first row, while the bottom row is the second row.
- The left column is the first column, while the right column is the second column.
In this form, \( a \), \( b \), \( c \), and \( d \) are numbers or expressions in the matrix's individual cells. These numbers can be whole numbers, fractions, or even variables, depending on how it's used in a problem or application.
matrix invertibility
When discussing the invertibility of matrices, it's critical to know that a matrix is invertible if there exists another matrix such that when both are multiplied together, the product is the identity matrix. However, not all matrices are invertible.
For a 2x2 matrix, whether or not it is invertible can be determined by calculating its determinant.
Understanding whether a matrix is invertible has many applications, such as solving systems of equations, where an invertible matrix often results in a unique solution.
For a 2x2 matrix, whether or not it is invertible can be determined by calculating its determinant.
- If the determinant is non-zero, there is an inverse, meaning the matrix is invertible.
- If the determinant is zero, the matrix does not have an inverse, or in other words, it is singular.
Understanding whether a matrix is invertible has many applications, such as solving systems of equations, where an invertible matrix often results in a unique solution.
determinant formula
The determinant formula for a 2x2 matrix is a simple yet powerful tool used frequently in linear algebra. This formula is essential for determining the properties of matrices, such as invertibility.
For a matrix of the form:\[\begin{bmatrix} a & b \c & d \end{bmatrix}\]The determinant, denoted as \( \text{det}(A) \), is calculated using the formula \( \text{det}(A) = ad - bc \).
Here's how it works:
For a matrix of the form:\[\begin{bmatrix} a & b \c & d \end{bmatrix}\]The determinant, denoted as \( \text{det}(A) \), is calculated using the formula \( \text{det}(A) = ad - bc \).
Here's how it works:
- Multiply the entry in the first row and first column with the entry in the second row and second column: \( a \times d \).
- Multiply the entry in the first row and second column with the entry in the second row and first column: \( b \times c \).
- Subtract the second product from the first: \( ad - bc \).
Other exercises in this chapter
Problem 56
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