Problem 57
Question
Solve each equation. $$ \log 5-\log x=1 $$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{1}{2}\).
1Step 1: Apply Logarithmic Identity
Use the logarithmic identity \[\log a - \log b = \log \left(\frac{a}{b}\right)\]to combine the logarithms on the left-hand side of the equation:\[\log 5 - \log x = \log \left(\frac{5}{x}\right)\]So the equation becomes:\[\log \left(\frac{5}{x}\right) = 1\]
2Step 2: Convert Logarithmic Equation to Exponential Form
Recall that if \(\log_b a = c\), then the equation can be rewritten in exponential form as \(a = b^c\). Here, the base is 10 (common logarithm), so\[\frac{5}{x} = 10^1\]which simplifies to\[\frac{5}{x} = 10\]
3Step 3: Solve for x
Cross-multiply to solve for \(x\):\[5 = 10x\]Divide both sides by 10 to isolate \(x\):\[x = \frac{5}{10}\]Simplify the fraction:\[x = \frac{1}{2}\]
Key Concepts
Logarithmic IdentitiesExponential FormCommon Logarithms
Logarithmic Identities
Logarithmic identities are key tools in simplifying and solving logarithmic equations. In this exercise, we use the identity \(\log a - \log b = \log \left(\frac{a}{b}\right)\). This identity helps you combine two logarithms into a single logarithm.
It’s derived from properties of exponents and is useful when dealing with subtraction of two logarithms.
It’s derived from properties of exponents and is useful when dealing with subtraction of two logarithms.
- This identity effectively condenses multiple logarithmic operations into one.
- It can simplify the equation, making it easier to solve.
- This concept can be extended to other bases beyond the common logarithm (base 10).
Exponential Form
The exponential form of an equation is a way to express the relationship between logarithms and exponents.
In our equation, we start with \(\log \left(\frac{5}{x}\right) = 1\). Knowing the base of the logarithm is 10 (since it's a common logarithm), we can convert this to its exponential form as \(\frac{5}{x} = 10^1\).
In our equation, we start with \(\log \left(\frac{5}{x}\right) = 1\). Knowing the base of the logarithm is 10 (since it's a common logarithm), we can convert this to its exponential form as \(\frac{5}{x} = 10^1\).
- This conversion from logarithmic to exponential form makes solving for variables straightforward.
- It’s like translating the equation into a form that's simpler to work with.
- Remember the general rule: if \(\log_b a = c\), then \(a = b^c\).
Common Logarithms
Common logarithms use the base 10 and are often implied without writing the base explicitly. For instance, \(\log 5\) and \(\log x\) in this exercise are actually \(\log_{10} 5\) and \(\log_{10} x\).
Recognizing the base is key, as it dictates how you proceed with solving the equations.
Recognizing the base is key, as it dictates how you proceed with solving the equations.
- Common logarithms are especially useful in scientific and engineering contexts due to their simplicity and relevance to decimal systems.
- They allow for the easy use of logarithmic identities, like the one used initially in this problem.
- Knowing that \(\log_{10} 10 = 1\) makes calculations involving \(10\) very convenient.
Other exercises in this chapter
Problem 57
Let \(f(x)=3 x-2\) and \(g(x)=x^{2}+x .\) Find each of the following. $$ (f \circ g)(4) $$
View solution Problem 57
Write each logarithm without an exponent or a radical symbol. Then simplify, if possible. See Example \(5 .\) $$ \log _{7}(\sqrt[5]{100})^{3} $$
View solution Problem 57
In Exercises 53–58, assume that there are no deposits or withdrawals. Compound Interest. If \(\$ 1\) had been invested on July \(4,1776,\) at \(5 \%\) interest,
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Solve for \(x .\) See Example 3. $$ \log _{5} x=-2 $$
View solution