Problem 57
Question
Solve by the method of your choice. In a race in which six automobiles are entered and there are no ties, in how many ways can the first four finishers come in?
Step-by-Step Solution
Verified Answer
The first four cars can finish in 360 different ways.
1Step 1: Understanding the Problem Statement
The problem is asking for the number of ways the first four cars can finish in a race with six cars, with the stipulation that there can be no ties.
2Step 2: Identify the Type of Problem
Because the order in which the cars finish is significant (1st, 2nd, 3rd, and 4th), this problem is a permutation type problem. Permutation is a counting method in combinatorial mathematics where the order of elements is significant.
3Step 3: Apply the Formula for Permutations
Use the formula for permutations, which is 'nPr=n!/(n-r)!', where 'n' is the total number of elements, 'r' is the number of elements to choose, and the '!' denotes the factorial operation. In this case, 'n' is 6 (the number of cars) and 'r' is 4 (the number of finishing positions).
4Step 4: Calculate the Permutations
Calculate the permutations 6P4 = 6!/(6-4)! = 6*5*4*3/2*1 = 30*12 = 360. So, there are 360 possible ways the first four cars can finish.
Other exercises in this chapter
Problem 56
Find the middle term in the expansion of $$\left(\frac{1}{x}-x^{2}\right)^{12}$$.
View solution Problem 56
Express each sum using summation notation. Use a lower limit of summation of your choice and k for the index of summation. $$6+8+10+12+\dots+32$$
View solution Problem 57
Explain how to find the probability of an event not occurring. Give an example.
View solution Problem 57
The graph shows that U.S. smokers have a greater probability of suffering from some ailments than the general adult population. Exercises \(57-58\) are based on
View solution