Problem 57
Question
Sketch the surfaces in Exercises \(13-76\) $$ x^{2}+z^{2}=1 $$
Step-by-Step Solution
Verified Answer
The surface is an infinite circular cylinder along the y-axis with a radius of 1.
1Step 1: Recognize the Equation Type
The equation \(x^2 + z^2 = 1\) is a standard form of a cylinder equation in the 3D space where \(x\) and \(z\) are related, while \(y\) is not involved in the equation.
2Step 2: Identify the Known Shape
The equation \(x^2 + z^2 = 1\) describes a circle in the 2D \(xz\)-plane with a radius of 1. This circle is centered at the origin (0, 0) in the \(xz\)-plane.
3Step 3: Extend the Shape along the y-axis
Since \(y\) does not appear in the equation, it indicates that the circle in the \(xz\)-plane extends infinitely along the \(y\)-axis, forming a circular cylinder.
4Step 4: Sketch the Cylinder
To sketch this surface, draw a circle of radius 1 in the \(xz\)-plane and then imagine extending this circle along the \(y\)-axis in both directions to form an infinite cylinder. This cylinder's shape does not change regardless of the \(y\)-coordinate.
5Step 5: Conclusion and Surface Characteristics
The sketched surface is a right circular cylinder with its axis along the \(y\)-axis. Its radius is 1, and it extends infinitely in the positive and negative \(y\)-direction, maintaining a consistent circular cross-section.
Key Concepts
Cylindrical SurfacesEquation of a CylinderSurface Sketching
Cylindrical Surfaces
Cylindrical surfaces are integral parts of 3D geometry. They are created when a curve in a plane is extended along an axis perpendicular to that plane. In essence, if you take a 2D shape, like a circle, and extend it straight along an axis that does not lie in the plane of the shape, you end up forming a cylinder.
To visualize this, think of wrapping a rectangle around to create a circular shape, giving you a tube-like structure. The most common cylindrical surface is the **circular cylinder**. However, cylinders can take on different cross-sectional shapes.
- **Elliptic cylinders** have ellipses as cross-sections.
- **Parabolic cylinders** have parabolas as cross-sections.
Equation of a Cylinder
The equation of a cylinder typically arises from the need to describe its surface in three-dimensional space. A basic form of this equation for a circular cylinder whose axis is aligned along a coordinate axis is relatively straightforward. For instance, when the axis is along the y-axis:The generic equation for this type of cylinder can be expressed as:\[x^2 + z^2 = r^2\]Where
- \(x\) and \(z\) are the variables that interact to form circles at different heights along the y-axis.
- \(r\) represents the radius of these circles.
- The absence of the \(y\)-variable shows that the circle in the \(xz\)-plane repeats for all values of \(y\).
Surface Sketching
Surface sketching in 3D geometry can seem daunting initially, but by following a few systematic steps, the complexity can be mitigated. When sketching a cylindrical surface, start by visualizing its base shape in two dimensions. In this case, it is a circle in the \(xz\)-plane.
- **Step 1**: Draw the circle at the origin, which is where both the \(x\) and \(z\) coordinates are zero.
- **Step 2**: Extend this circle along the axis not involved in its equation, which is the \(y\)-axis in our example.
Other exercises in this chapter
Problem 56
In Exercises 53–56, find the point in which the line meets the plane. $$ x=-1+3 t, \quad y=-2, \quad z=5 t ; \quad 2 x-3 z=7 $$
View solution Problem 56
Show that the point \(P(3,1,2)\) is equidistant from the points \(A(2,-1,3)\) and \(B(4,3,1)\)
View solution Problem 57
Find parametrizations for the lines in which the planes in Exercises 57–60 intersect. $$ x+y+z=1, \quad x+y=2 $$
View solution Problem 58
Find parametrizations for the lines in which the planes in Exercises 57–60 intersect. $$ 3 x-6 y-2 z=3, \quad 2 x+y-2 z=2 $$
View solution