Problem 57
Question
Sketch the graph of \(h=-6 t+30\) using the horizontal axis for \(t\) values and the vertical axis for \(h\) values.
Step-by-Step Solution
Verified Answer
Plot the y-intercept (0, 30), use the slope to find another point (1, 24), and draw the line through these points.
1Step 1: Identify the slope and y-intercept
The given equation of the line is in slope-intercept form: \[ h = -6t + 30 \]Here, the slope (m) is -6 and the y-intercept (b) is 30.
2Step 2: Plot the y-intercept
Start by plotting the y-intercept on the graph. The y-intercept occurs at \( t = 0 \). So, when \( t = 0 \), \( h = 30 \). Plot the point (0, 30) on the graph.
3Step 3: Use the slope to find another point
The slope of -6 means that for every increase of 1 unit in \( t \), \( h \) decreases by 6 units. From the point (0, 30), move one unit to the right (increase \( t \) by 1), and then move 6 units down (decrease \( h \) by 6). This gives us the point (1, 24). Plot this point.
4Step 4: Draw the line
Connect the points (0, 30) and (1, 24) with a straight line. This represents the graph of the equation \( h = -6t + 30 \). Extend the line in both directions.
Key Concepts
slope-intercept formgraphing linear functionsy-intercept
slope-intercept form
To understand how to graph linear functions like the one in the exercise, we first need to understand the slope-intercept form. The slope-intercept form is written as \[ y = mx + b \] where
- m is the slope of the line, which tells us how steep the line is.
- b is the y-intercept, which is the point where the line crosses the vertical (y) axis.
- The slope (m) is -6, which means the line slopes downwards. For every unit increase in t, h decreases by 6 units.
- The y-intercept (b) is 30. This is where the line crosses the y-axis.
graphing linear functions
Graphing linear functions involves several clear steps that make the process easier and error-free. Here's how you can graph any linear function:
- Identify the slope and y-intercept: As seen in our exercise, the given equation is already in slope-intercept form. Easily spot the slope and y-intercept.
- Plot the y-intercept: The y-intercept is where the line hits the y-axis. For our equation \( h = -6t + 30 \), the y-intercept is 30.
- Plot additional points using the slope: From the y-intercept, use the slope to find more points. Since our slope is -6, move one unit to the right and 6 units down to get another point on the line.
- Draw the line: Connect your points with a straight line and extend it in both directions.
y-intercept
The y-intercept is a crucial concept when it comes to graphing linear equations. It's the point where the line crosses the y-axis, and it often provides our first starting point for graphing. Here's what you need to know about the y-intercept:
- Position on the Graph: For any linear function in the form \[ y = mx + b \] the y-intercept is the value of b. This is where our line intersects the y-axis when \[ x = 0 \] In our exercise, when t (or x) is 0, \[ h = 30 \] Therefore, the y-intercept is (0, 30).
- Starting Point for Graphing: Begin plotting your line by marking the y-intercept on the graph, then use the slope to plot more points.
- Vertical Crossing: The y-intercept tells us the value of the line at the exact moment it crosses the y-axis, providing a vital reference point for understanding where the line lies on the graph.
Other exercises in this chapter
Problem 57
Write an equation of the line that passes through the point \((-3,0)\) and is parallel to the line whose equation is \(y=-x+4\)
View solution Problem 57
Plot a few points that satisfy the equation \(y=x^{2} .\) Do you think the graph of this equation is a straight line? Explain.
View solution Problem 58
Write an equation of the line that passes through the point \((2,-1)\) and is parallel to the line whose equation is \(4 x-3 y=6\)
View solution Problem 58
Plot a few points that satisfy the equation \(y=x^{3} .\) Do you think the graph of this equation is a straight line? Explain.
View solution