Problem 57
Question
Removing Vascular Lesions. A pulsed dye laser emits light of wavelength 585 \(\mathrm{nm}\) in \(450-\mu\) s pulses. Because this wave- length is strongly absorbed by the hemoglobin in the blood, the method is especially effective for removing various types of blemishes due to blood, such as port-wine- colored birth-marks. To get a reasonable estimate of the power required for such laser surgery, we can model the blood as having the same specific heat and heat of vaporization as water \(\left(4190 \mathrm{J} / \mathrm{kg} \cdot \mathrm{K}, 2.256 \times 10^{6} \mathrm{J} / \mathrm{kg}\right) .\) Suppose that each pulse must remove 2.0\(\mu g\) of blood by evaporating it, starting at \(33^{\circ} \mathrm{C}\) (a) How much energy must each pulse deliver to the blemish? (b) What must be the power output of this laser? (c) How many photons does each pulse deliver to the blemish?
Step-by-Step Solution
VerifiedKey Concepts
Pulsed Dye Laser
Wavelength 585 nm
Specific Heat and Heat of Vaporization
On the other hand, the heat of vaporization is the energy required to change a unit mass of a substance from a liquid to a vapor at its boiling point. For blood, again compared to water, this is 2.256 x 10^6 J/kg. Combining these concepts allows us to calculate the total energy needed to both heat and vaporize a small amount of blood, using the laser treatment discussed.
Calculating Energy and Power
- Heating energy: \( q_1 = mc\Delta T \), where \( m \) is mass, \( c \) is specific heat capacity, and \( \Delta T \) is the temperature change needed.
- Vaporizing energy: \( q_2 = mL_v \), where \( L_v \) is the heat of vaporization.