Problem 57
Question
Prove the strong version of mathematical induction, using the weak version.
Step-by-Step Solution
Verified Answer
To prove the strong version of mathematical induction using the weak version, we first formally define both versions. Let P(n) be the statement involving positive integers. The weak induction holds for statement R(n):
1. R(1) is true (base case).
2. If R(k) is true, then R(k+1) is true (induction step).
We define the statement for strong induction, P(n), as: P(n) is true if P(j) is true for all 1≤j≤n. We then show that P(n) also holds under the conditions of weak induction:
1. P(1) is trivially true.
2. Assuming P(k) is true, meaning R(j) is true for all 1≤j≤k, we find that if R(k) is true, then R(k+1) is also true. Therefore, P(k+1) is true, since R(j) is true for all 1≤j≤(k+1).
Thus, strong induction is proven using weak induction.
1Step 1: State the strong and weak versions of induction formally
First, let's denote the two versions of induction formally.
Let P(n) be a statement for any positive integer n.
1. Weak Induction:
a. P(1) is true (base case).
b. If P(k) is true, then P(k+1) is true (induction step).
2. Strong Induction:
a. P(1) is true (base case).
b. If P(j) is true for all 1≤j≤k, then P(k+1) is true (induction step).
2Step 2: Assume weak induction holds for some statement R
Suppose we have a statement R(n) and the weak induction holds for R, i.e.,
a. R(1) is true (base case).
b. If R(k) is true, then R(k+1) is true (induction step).
3Step 3: Define the statement for strong induction
Now, we want to prove the strong version of induction using the weak version. First, we need to define a statement P(n) that still holds using strong induction.
Define P(n) as: P(n) is true if P(j) is true for all 1≤j≤n. Note that this differs from the statement R(n), where R(n) does not specify any relation to prior integers.
4Step 4: Show that P holds for the weak version of induction
We want to show that our statement P(n) also holds under the conditions of weak induction, i.e.,
a. P(1) is true.
b. If P(k) is true, then P(k+1) is true.
By definition of P(n), P(1) is trivially true, since it says that P(n) is true for all positive integers less than or equal to 1 (which is just 1).
Now let's assume P(k) is true, meaning R(j) is true for all 1≤j≤k. Based on our assumptions for weak induction, if R(k) is true, then R(k+1) is also true. Consequently, P(k+1) is true since R(j) is true for all 1≤j≤(k+1).
Thus, weak induction holds for P(n), and hence, strong induction is proven using weak induction.
Key Concepts
Strong InductionWeak InductionProof TechniquesDiscrete Mathematics
Strong Induction
Strong induction, also known as complete induction, is an essential proof technique in mathematics. This technique demonstrates that a property or proposition applies to all natural numbers. To understand strong induction, it's essential to break it down into parts:
- The Base Case: We start by proving that the property holds for the initial value, usually when \( n = 1 \). This is similar to weak induction.
- The Inductive Step: Instead of assuming the property only holds for \( n = k \) to prove it for \( n = k+1 \), in strong induction, we assume it holds for all values from 1 to \( k \). This broader assumption can make it easier to prove the property for the next number.
- Conclusion: If both steps are satisfied, then the property must be true for all natural numbers, \( n \).
Weak Induction
Weak induction, often simply called mathematical induction, is widely used for proving the validity of statements for all natural numbers. This technique consists of two main parts:
- The Base Case: This initial step involves verifying that a statement holds true for the first natural number, often \( n = 1 \).
- The Inductive Step: For this step, we assume that the statement is true for some arbitrary natural number \( k \). We then prove it is also true for \( k+1 \).
- Finalizing: If both the base case and induction step are proven, this confirms that the statement is true for all natural numbers.
Proof Techniques
Proof techniques are formal methods used to establish the truth of mathematical statements. Among these techniques, mathematical induction stands out for its structured approach and is commonly introduced in discrete mathematics courses.
In the realm of induction, both weak and strong forms serve different purposes:
- Weak Induction: Suitable for cases where each instance relies solely on the previous one.
- Strong Induction: Necessary when a case relies on multiple previous ones, broadening the proof base.
Discrete Mathematics
Discrete mathematics is an important branch of mathematics focused on countable, distinct, and often finite structures. Unlike continuous mathematics, which deals with functions and limits, discrete mathematics focuses on:
This branch of mathematics is integral to fields such as cryptography, computer modeling, and network analysis, highlighting its relevance in both theoretical and applied contexts.
- Graph theory, which explores networks of points connected by lines.
- Combinatorics, which examines ways of counting and arranging objects.
- Logic and Boolean algebra, fundamental in computer science for circuit design.
This branch of mathematics is integral to fields such as cryptography, computer modeling, and network analysis, highlighting its relevance in both theoretical and applied contexts.
Other exercises in this chapter
Problem 55
Prove that any postage of \(\mathrm{n}(\geq 2)\) cents can be made using two- and three-cent stamps. (Hint: Use the division algorithm and induction.)
View solution Problem 56
Let \(a\) and \(b\) be any two positive integers with \(a \geq b\). Using the sequence of equations in the euclidean algorithm prove that \(\operatorname{gcd}\\
View solution Problem 58
Prove the weak version of induction, using the well-ordering principle.
View solution Problem 59
Let \(S_{n}\) denote the sum of the elements in the \(n\) th set of the sequence of sets of squares \(\\{1\\},\\{4,9\\},\\{16,25,36\\}, \ldots .\) Find a formul
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