Problem 57
Question
Perform the indicated operations. $$(2 z+y)(3 z-4 y)$$
Step-by-Step Solution
Verified Answer
The product is \(6z^2 - 5yz - 4y^2\).
1Step 1: Identify Terms for Multiplication
We have two binomials to multiply: \((2z + y)\) and \((3z - 4y)\). Our task is to expand this product using the distributive property (also known as the FOIL method for binomials).
2Step 2: Multiply the First Terms
Multiply the first terms from each binomial: \(2z\) from the first binomial and \(3z\) from the second binomial. So: \[2z \times 3z = 6z^2\]
3Step 3: Multiply the Outer Terms
Next, multiply the outer terms: \(2z\) from the first and \(-4y\) from the second. This gives: \[2z \times (-4y) = -8zy\]
4Step 4: Multiply the Inner Terms
Now multiply the inner terms: \(y\) from the first and \(3z\) from the second. Thus: \[y \times 3z = 3yz\]
5Step 5: Multiply the Last Terms
Finally, multiply the last terms from each binomial: \(y\) and \(-4y\). This results in: \[y \times (-4y) = -4y^2\]
6Step 6: Combine Like Terms
Now add all the terms together: \[6z^2 - 8zy + 3yz - 4y^2\] Notice that \(-8zy\) and \(3yz\) are like terms. Combine them: \[6z^2 + (-8zy + 3yz) - 4y^2 = 6z^2 - 5zy - 4y^2\]
7Step 7: Simplified Expression
The simplified expression after applying all the operations is: \[6z^2 - 5yz - 4y^2\]
Key Concepts
Distributive PropertyFOIL MethodLike Terms
Distributive Property
The distributive property is a fundamental principle of algebra that allows us to multiply a single term by each term inside a bracket. In the context of binomial multiplication, it ensures that each term in one binomial is multiplied by each term in the other.
Imagine you have to distribute candies equally; similarly, in mathematics, you distribute the multiplication across terms.
Imagine you have to distribute candies equally; similarly, in mathematics, you distribute the multiplication across terms.
- The property is mathematically expressed as: \ a(b + c) = ab + ac \.
- For the exercise \( (2z+y)(3z-4y) \), this means multiplying every term in the first binomial by every term in the second.
FOIL Method
The FOIL method is a special application of the distributive property for binomials, where FOIL stands for First, Outer, Inner, Last. This mnemonic helps remember the sequence of multiplications necessary to expand two binomials effectively.
- **First**: Multiply the first terms of each binomial. For \( (2z+y)(3z-4y) \), that is \((2z)\times(3z) = 6z^2\).
- **Outer**: Multiply the outer terms. For our binomials, \((2z)\times(-4y) = -8zy\).
- **Inner**: Multiply the inner terms: \(y\times3z = 3yz\).
- **Last**: Multiply the last terms: \(y\times(-4y) = -4y^2\).
Like Terms
In algebra, like terms are terms that have identical variable parts and can therefore be combined to simplify expressions. Understanding and identifying like terms is crucial in simplifying your final expression after expansion using distributive property or the FOIL method.
- Like terms are terms that contain the same variables with the same powers. For example, in \(6z^2 - 8zy + 3yz - 4y^2\), \(-8zy\) and \(3yz\) are like terms as they both contain the variables \(z\) and \(y\) raised to the first power.
- Combining like terms means adding or subtracting their coefficients: \(-8zy + 3yz\) simplifies to \(-5yz\).
Other exercises in this chapter
Problem 57
Factor each sum or difference of cubes completely. $$(r+6)^{3}-216$$
View solution Problem 57
Find each sum or difference. $$\frac{1}{a^{2}-5 a+6}-\frac{1}{a^{2}-4}$$
View solution Problem 58
If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\sqrt[4]{\sqrt[3]{2}}$$
View solution Problem 58
Find each product. Assume that all variables represent positive real numbers. $$\left(2 z^{1 / 2}+z\right)\left(z^{1 / 2}-z\right)$$
View solution