Problem 57
Question
Let \(f(x)=\sec ^{2}(x)-\tan ^{2}(x) .\) Use the Product Rule to differentiate each summand of \(f\). Simplify to show that \(f^{\prime}(x)=0\) for each \(x\) in the domain of \(f .\) How can you obtain this result more easily?
Step-by-Step Solution
Verified Answer
Differentiate using the product rule and trigonometric identities: \(f'(x) = 0\). Recognize that \(f(x) = 1\).
1Step 1: Identify and Differentiate the First Summand
The first summand is \(\sec^2(x)\). The derivative of \(\sec^2(x)\) using the chain rule is: \[\frac{d}{dx}[\sec^2(x)] = 2\sec(x)\cdot \sec(x) \tan(x) = 2\sec^2(x) \tan(x)\]
2Step 2: Identify and Differentiate the Second Summand
The second summand is \(\tan^2(x)\). The derivative using the chain rule is: \[\frac{d}{dx}[\tan^2(x)] = 2\tan(x)\cdot \sec^2(x) = 2\tan(x)\sec^2(x)\]
3Step 3: Combine the Derivatives
Combine the derivatives of both summands to find \(f'(x)\):\[f'(x) = 2\sec^2(x)\tan(x) - 2\tan(x)\sec^2(x)\]Both terms are identical but of opposite signs, so they cancel each other out: \[f'(x) = 0\]
4Step 4: Verification Using Trigonometric Identities
Notice that \(\sec^2(x) - \tan^2(x) = 1\), a known trigonometric identity derived from \(\sec^2(x) - \tan^2(x) = \cos^{-2}(x) - \frac{\sin^2(x)}{\cos^2(x)} = 1\). Since \(f(x) = 1\), its derivative is clearly \(f'(x) = 0\).
Key Concepts
Product RuleChain RuleTrigonometric IdentitiesSecantTangent
Product Rule
The Product Rule is an essential formula used in differentiation when you need to find the derivative of a product of two functions. It's expressed mathematically as:
- If you have two functions, say \( u(x) \) and \( v(x) \), the derivative of their product \( u(x) \cdot v(x) \) is given by: \( (uv)' = u'v + uv' \).
Chain Rule
The Chain Rule is an indispensable tool in calculus. It helps us find derivatives of composite functions, those created when one function is nested inside another. Written succinctly, the Chain Rule states:
- If you have a composite function \( g(f(x)) \), the derivative is \( g'(f(x)) \cdot f'(x) \).
Trigonometric Identities
Trigonometric identities often simplify complex expressions, making differentiation and integration much easier. In our example, we see the utility of one such identity:
- \( \sec^2(x) - \tan^2(x) = 1 \).
Secant
The secant function, represented as \( \sec(x) \), is the reciprocal of the cosine function: \( \sec(x) = \frac{1}{\cos(x)} \). Differentiating \( \sec(x) \) involves some complexity since we need to apply the Chain Rule along with basic knowledge of how reciprocal functions behave.To derive \( \sec(x) \), we use the knowledge that:
- \( \frac{d}{dx}\sec(x) = \sec(x)\tan(x) \).
Tangent
The tangent function, denoted as \( \tan(x) \), is one of the basic trigonometric functions and is defined as \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). Known for its repetitive pattern and vertical asymptotes, it behaves uniquely, especially under differentiation.The derivative of \( \tan(x) \) is:
- \( \frac{d}{dx}\tan(x) = \sec^2(x) \).
Other exercises in this chapter
Problem 57
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