Problem 57
Question
Graph equation in a rectangular coordinate system. $$3 x-18=0$$
Step-by-Step Solution
Verified Answer
The graph of the equation \(3x - 18 = 0\) is a vertical line that passes through the x-axis at \(x = 6\).
1Step 1: Rearrange the Equation
The given equation is \(3x - 18 = 0\). We can rewrite this equation to get \(x\) alone on one side. This is done by adding 18 to both sides of the equation and then dividing both sides by 3 and we get \(x = 6\).
2Step 2: Plot the Graph
The equation \(x = 6\) represents a vertical line passing through the point (6, 0) on the x-axis, as well as through every other point where \(x = 6\). In other words, the line passes through points such as (6, 1), (6, -1), (6, 2), etc. Therefore, plot a vertical line that passes through these points.
Key Concepts
Rectangular Coordinate SystemVertical LinesSolving Linear Equations
Rectangular Coordinate System
The rectangular coordinate system is a fundamental concept used in graphing equations. It provides a grid to help visualize mathematical equations and data. This system is composed of two perpendicular number lines that intersect at their zero points, known as the origin.
The horizontal line is known as the x-axis, and the vertical line is known as the y-axis. These axes split the plane into four quadrants, which help in locating any point with ordered pairs \((x, y)\).
The horizontal line is known as the x-axis, and the vertical line is known as the y-axis. These axes split the plane into four quadrants, which help in locating any point with ordered pairs \((x, y)\).
- The first quarter is where both coordinates are positive.
- The second quarter features a negative x and a positive y.
- The third quarter has both coordinates negative.
- The fourth has a positive x and a negative y.
Vertical Lines
In the rectangular coordinate system, vertical lines are a special type of line where all points share the same x-coordinate. This means that a vertical line does not rely on the y-coordinate to position its points, as all changes occur perpendicular to the x-axis.
For example, a graph of the equation \(x = 6\) results in a vertical line crossing through the x-axis at 6. This line passes through points such as \((6, 0)\), \((6, 1)\), \((6, -1)\), and essentially any point where \(x = 6\).
The nature of a vertical line shows that it does not have a slope in the traditional sense—it's often considered undefined—because there is no horizontal change to accompany the vertical one within the line.
Key points about vertical lines include:
For example, a graph of the equation \(x = 6\) results in a vertical line crossing through the x-axis at 6. This line passes through points such as \((6, 0)\), \((6, 1)\), \((6, -1)\), and essentially any point where \(x = 6\).
The nature of a vertical line shows that it does not have a slope in the traditional sense—it's often considered undefined—because there is no horizontal change to accompany the vertical one within the line.
Key points about vertical lines include:
- They are parallel to the y-axis.
- All points on the line share the same x-coordinate.
- They do not intersect the y-axis unless that axis represents the same x-coordinate.
Solving Linear Equations
Solving linear equations is a fundamental skill in mathematics, crucial for graphing and understanding a wide range of problems. It involves finding the values of the variables that make the equation true. For any given linear equation, such as \(3x - 18 = 0\), the goal is to isolate the variable, in this case, x.
Here is a simplified step-by-step process:
Here is a simplified step-by-step process:
- Rearrange the equation to isolate terms with the variable on one side. For \(3x - 18 = 0\), add 18 to both sides to have \(3x = 18\).
- Divide each term by the coefficient of the variable, here 3, leading to \(x = \frac{18}{3} = 6\).
- This solution indicates the value of the variable that satisfies the equation.
Other exercises in this chapter
Problem 57
Find. a. \((f \circ g)(x)\) b. \((g \circ f)(x)\) c. \((f \circ g)(2)\) d. \((g \circ f)(2)\) $$f(x)=x^{2}+2, g(x)=x^{2}-2$$
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Begin by graphing the standard quadratic function, \(f(x)=x^{2} .\) Then use transformations of this graph to graph the given function. $$h(x)=-(x-2)^{2}$$
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Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}+y^{2}+12 x-6 y-4=0$$
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Evaluate each piece wise function at the given values of the independent variable. \(h(x)=\left\\{\begin{array}{ccc}\frac{x^{2}-25}{x-5} & \text { if } & x \neq
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