Problem 57
Question
For the following exercises, write a system of equations that represents the situation. Then, solve the system using the inverse of a matrix. A clothing store needs to order new inventory. It has three different types of hats for sale: straw hats, beanies, and cowboy hats. The straw hat is priced at \$13.99, the beanie at \(\$ 7.99\), and the cowboy hat at \(\$ 14.49 .\) If 100 hats were sold this past quarter, \(\$ 1,119\) was taken in by sales, and the amount of beanies sold was 10 more than cowboy hats, how many of each should the clothing store order to replace those already sold?
Step-by-Step Solution
Verified Answer
30 straw hats, 40 beanies, and 30 cowboy hats.
1Step 1: Define Variables
Let \( s \) be the number of straw hats, \( b \) be the number of beanies, and \( c \) be the number of cowboy hats sold. These will be our variables of interest that we want to solve for.
2Step 2: Setup the System of Equations
We have three pieces of information to create the system of equations. 1. **Total Hats**: Altogether, 100 hats were sold: \( s + b + c = 100 \).2. **Total Income**: The total income was $1119: \( 13.99s + 7.99b + 14.49c = 1119 \).3. **Beanie Relationship**: There were 10 more beanies than cowboy hats: \( b = c + 10 \).
3Step 3: Transform Equation 3
Substitute the third equation, \( b = c + 10 \), into the other equations (to simplify) where relevant. This reduces the system to two variables \(s, c\) in equations 1 and 2.
4Step 4: Substitute into the Equations
Substitute \( b = c + 10 \) into equation 1: - \(s + (c + 10) + c = 100\)- Simplifies to: \( s + 2c = 90 \).
5Step 5: Substitute b in the Income Equation
Substitute \( b = c + 10 \) into equation 2:- \( 13.99s + 7.99(c + 10) + 14.49c = 1119 \)- Expanding gives: \( 13.99s + 7.99c + 79.9 + 14.49c = 1119 \)- Which simplifies to: \( 13.99s + 22.48c = 1039.10 \).
6Step 6: Matrix Representation
Represent the system of equations \( s + 2c = 90 \) and \( 13.99s + 22.48c = 1039.10 \) as a matrix equation:\[\begin{bmatrix} 1 & 2 \ 13.99 & 22.48 \end{bmatrix}\begin{bmatrix} s \ c \end{bmatrix} = \begin{bmatrix} 90 \ 1039.10 \end{bmatrix}\]
7Step 7: Find the Inverse of the Coefficient Matrix
Calculate the inverse of the coefficient matrix: \[A^{-1} = \frac{1}{det(A)} \cdot \begin{bmatrix} A_{22} & -A_{12} \ -A_{21} & A_{11} \end{bmatrix}\]Evaluate the determinant and inverse.
8Step 8: Compute the Solution Using the Inverse
Multiply the inverse matrix by the constants to find solutions for \( s \) and \( c \). From \( A^{-1}b = x \), solve to get values of \( s, c \).
9Step 9: Substitute Back to Find b
Having found \( s \) and \( c \), use \( b = c + 10 \) to find \( b \).
10Step 10: Verify the Solution
Check solutions by substituting back into the original equations to ensure the system is correctly satisfied.
Key Concepts
Matrix InverseLinear AlgebraSolving Word Problems
Matrix Inverse
When dealing with systems of equations, the matrix inverse is a powerful tool that can simplify the process. The idea is that if you have a matrix equation like \( AX = B \), where \( A \) is a square matrix, the solution \( X \) can be acquired by multiplying both sides of the equation by the inverse of \( A \) to get \( X = A^{-1}B \). So, what exactly is a matrix inverse?
- **Definition:** The inverse of a matrix \( A \) is another matrix, denoted \( A^{-1} \), such that when it is multiplied by \( A \), yields the identity matrix: \( AA^{-1} = I \).
- **Existence:** Not all matrices have inverses. A matrix must be square (same number of rows and columns) and have a non-zero determinant to have an inverse.
Linear Algebra
Linear algebra is the branch of mathematics dealing with vectors, vector spaces, matrices, and linear transformations. It plays a vital role in solving systems of equations like our clothing store problem.
- **Vectors and Matrices:** A matrix is simply an array of numbers, and each element of the matrix is called a vector. For example, in our problem, we set up a matrix equation to represent the coefficients of the system of equations.
- **Operations:** Linear algebra allows various operations, such as addition, multiplication, and finding inverses, which are critical when solving matrix equations.
Solving Word Problems
Solving word problems can often be challenging because they require translating real-world situations into mathematical terms. Here's how to approach solving a word problem like the one in our clothing store exercise:
- **Understand the Problem:** Carefully read the problem to understand what is being asked. Identify relevant information, such as total sales or relationships between quantities.
- **Define Variables:** Use variables to represent unknown quantities. In our exercise, \( s \), \( b \), and \( c \) represented straw hats, beanies, and cowboy hats, respectively.
- **Set Up Equations:** Use the information provided to form equations. For example, total sales and pricing details led to two equations in the store's exercise.
- **Solve the Equations:** Choose an appropriate method to solve the system. We used matrix inverse techniques, but other methods could be graphing, substitution, or elimination.
- **Verify the Solution:** Substitute the solutions back into the original problem to ensure they make sense and satisfy all conditions.
Other exercises in this chapter
Problem 56
For the following exercises, solve for the desired quantity. A stuffed animal business has a total cost of production \(C=12 x+30\) and a revenue function \(R=2
View solution Problem 57
For the following exercises, create a system of linear equations to describe the behavior. Then, solve the system for all solutions using Cramer's Rule. You dec
View solution Problem 57
For the following exercises, set up the augmented matrix that describes the situation, and solve for the desired solution. A major appliance store is considerin
View solution Problem 57
For the following exercises, use the matrix below to perform the indicated operation on the given matrix. \(B=\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 0 & 1 \\
View solution