Problem 57
Question
For the following exercises, use the vertex of the graph of the quadratic function and the direction the graph opens to find the domain and range of the function. Vertex \((-1,2)\) opens down.
Step-by-Step Solution
Verified Answer
Domain is all real numbers; Range is \(y \leq 2\).
1Step 1: Understand the Problem
The function has a vertex at \((-1, 2)\) and opens downward, which means it is a quadratic function with a maximum point at its vertex.
2Step 2: Determine the Domain
For any quadratic function, the domain is the set of all possible x-values. Since there are no restrictions on the x-values for a quadratic function, the domain is all real numbers.
3Step 3: Determine the Range
Since the function opens downward, the vertex provides the highest y-value. The range consists of all y-values less than or equal to the y-coordinate of the vertex, which is 2. Therefore, the range is \(y \leq 2\).
Key Concepts
Domain and RangeVertex of a Quadratic FunctionGraph of Quadratic Functions
Domain and Range
When dealing with quadratic functions, it's essential to understand the concepts of domain and range as they outline the extents of the function.
The **domain** of a quadratic function is straightforward. It encompasses all real numbers, meaning there are no restrictions on the input values (x-values). Whether the graph of the quadratic function opens upwards or downwards, the x-values can take any real number. Therefore, it can be represented as:
For a parabola that opens downward (like our example), the vertex represents the highest point on the graph. Thus, all other points have a y-value less than or equal to the y-value of the vertex. In this case, if the vertex is at \( (-1, 2) \) and the parabola opens downward, the range is:
The **domain** of a quadratic function is straightforward. It encompasses all real numbers, meaning there are no restrictions on the input values (x-values). Whether the graph of the quadratic function opens upwards or downwards, the x-values can take any real number. Therefore, it can be represented as:
- The domain is \( x \in \mathbb{R} \), meaning all real numbers.
For a parabola that opens downward (like our example), the vertex represents the highest point on the graph. Thus, all other points have a y-value less than or equal to the y-value of the vertex. In this case, if the vertex is at \( (-1, 2) \) and the parabola opens downward, the range is:
- All y-values such that \( y \leq 2 \).
Vertex of a Quadratic Function
The vertex of a quadratic function provides us with valuable information about the graph of the function. It's the most critical point in the function because it indicates either the highest or lowest point depending on the parabola's direction.
In a standard quadratic equation of the form \( y = ax^2 + bx + c \), the vertex can be found using the vertex formula \( x = -\frac{b}{2a} \). The vertex coordinates are \( (h, k) \), where \( h \) comes from the formula, and \( k \) is the y-value when you plug \( h \) back into the equation.
Once you have the vertex, you can determine important characteristics of the quadratic function:
In a standard quadratic equation of the form \( y = ax^2 + bx + c \), the vertex can be found using the vertex formula \( x = -\frac{b}{2a} \). The vertex coordinates are \( (h, k) \), where \( h \) comes from the formula, and \( k \) is the y-value when you plug \( h \) back into the equation.
Once you have the vertex, you can determine important characteristics of the quadratic function:
- If the parabola opens upwards, the vertex is the lowest point, called the minimum.
- If it opens downwards, like in our example, it is the highest point, called the maximum.
Graph of Quadratic Functions
Graphing a quadratic function involves plotting its characteristic U-shape called a parabola. The shape of the parabola depends on the direction it opens, which influences the function's range and behavior.
There are several steps to visualize the graph of a quadratic function:
There are several steps to visualize the graph of a quadratic function:
- **Identify the Vertex:** This is your starting point since it's the maximum or minimum point depending on the opening direction.
- **Determine the Axis of Symmetry:** A vertical line through the vertex divides the parabola into two mirror images. For our example, the axis of symmetry is \( x = -1 \).
- **Identify if the Parabola Opens Upwards or Downwards:** Check the sign of \( a \) in the equation \( y = ax^2 + bx + c \). If \( a > 0 \), it opens upwards, and if \( a < 0 \), it opens downwards.
- **Plot Additional Points:** Select x-values on either side of the vertex, calculate corresponding y-values, and plot to understand the curve's spread.
Other exercises in this chapter
Problem 57
For the following exercises, use the given information to answer the questions. The current in a circuit varies inversely with its resistance measured in ohms.
View solution Problem 57
For the following exercises, graph the polynomial functions using a calculator. Based on the graph, determine the intercepts and the end behavior. $$ f(x)=x^{4}
View solution Problem 57
Graph the polynomial functions using a calculator. Based on the graph, determine the intercepts and the end behavior. $$f(x)=x^{4}-81$$
View solution Problem 58
For the following exercises, list all possible rational zeros for the functions. \(f(x)=3 x^{3}+5 x^{2}-5 x+4\)
View solution