Problem 57
Question
Find an equation for the line satisfying the given conditions. Through (-2,1) with slope 3.
Step-by-Step Solution
Verified Answer
Answer: The equation of the line is y = 3x + 7.
1Step 1: Write down the given information
The given point is (-2, 1) and the slope, m, is 3.
2Step 2: Use the slope-point form of a linear equation
We will use the slope-point form (y - y1) = m (x - x1) to find the equation of the line.
3Step 3: Substitute the point and slope into the formula
Plug in the given point (-2, 1) and the slope, m = 3, into the slope-point form of a linear equation:
(y - 1) = 3 (x - (-2))
4Step 4: Simplify the equation
Now, we simplify the equation to get the equation of the line:
(y - 1) = 3 (x + 2)
Now, distribute the 3 to both (x + 2) terms:
y - 1 = 3x + 6
Next, add 1 to both sides of the equation to isolate y:
y = 3x + 7
5Step 5: Write the final equation of the line
Thus, the equation of the line is:
y = 3x + 7
Key Concepts
Slope-Point FormSlopeEquation of a Line
Slope-Point Form
The slope-point form is a powerful tool in linear algebra that helps us quickly find the equation of a line when we know a point on the line and its slope. The formula is written as \[ (y - y_1) = m(x - x_1) \] where
Once the formula is set up, solving for \( y \) allows us to express the equation in the more familiar slope-intercept form, \( y = mx + b \). This makes it easy to graph or further manipulate the equation as needed.
- \( y_1 \) is the y-coordinate of the given point,
- \( x_1 \) is the x-coordinate of the given point,
- \( m \) is the slope of the line.
Once the formula is set up, solving for \( y \) allows us to express the equation in the more familiar slope-intercept form, \( y = mx + b \). This makes it easy to graph or further manipulate the equation as needed.
Slope
The concept of slope is pivotal in understanding linear equations. Slope measures how steep a line is, or how quickly it rises or falls as you move along it horizontally. Mathematically, the slope \( m \) is determined by the ratio of the vertical change (often referred to as the "rise") to the horizontal change (the "run") of a line between two points.In formula terms, the slope \( m \) is expressed as:\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
For a positive slope, the line moves upwards as it goes from left to right. For a negative slope, the line falls as it moves from left to right. Understanding slope is crucial because it characterizes the direction and steepness of a line, which can be universally applied across various mathematical and real-world problems, from graphing lines to predicting trends.In our exercise, the slope is given as 3, which means for every unit increase horizontally, the line rises by three units vertically. This steepness directly influences the final equation and its graphical representation.
For a positive slope, the line moves upwards as it goes from left to right. For a negative slope, the line falls as it moves from left to right. Understanding slope is crucial because it characterizes the direction and steepness of a line, which can be universally applied across various mathematical and real-world problems, from graphing lines to predicting trends.In our exercise, the slope is given as 3, which means for every unit increase horizontally, the line rises by three units vertically. This steepness directly influences the final equation and its graphical representation.
Equation of a Line
An equation of a line is a mathematical statement that describes all the points on that line. When we know the slope and a point through which the line passes, we can write this equation.
One common form of the line equation is the slope-intercept form, given by:\[ y = mx + b \]where
One common form of the line equation is the slope-intercept form, given by:\[ y = mx + b \]where
- \( m \) is the slope of the line, and
- \( b \) is the y-intercept, the point where the line crosses the y-axis.
Other exercises in this chapter
Problem 56
Express the given number in normal decimal notation. Electron charge: \(1.602 \times 10^{-27}\) coulomb
View solution Problem 56
Use a calculator to find approximate solutions of the equation. $$7.63 x^{2}+2.79 x=5.32$$
View solution Problem 57
Find the equation of the circle with given center and radius \(r\). $$(0,0) ; \quad r=\sqrt{3}$$
View solution Problem 57
Find all real solutions of the equation exactly. $$y^{4}-7 y^{2}+6=0$$
View solution