Problem 57
Question
Factor using the formula for the sum or difference of two cubes. $$x^{3}+27$$
Step-by-Step Solution
Verified Answer
The factorized form of \(x^3 + 27\) using the formula for the sum of two cubes is \((x + 3)(x^2 - 3x + 9)\).
1Step 1: Identify a and b in the problem
Taking \(x^3 + 27\) as \(a^3 + b^3\), we can identify \(a = x\) and \(b = 3\).
2Step 2: Substitute a and b into the formula
Now we need to substitute \(a = x\) and \(b = 3\) into the formula \(a^3 + b^3 = (a+b)(a^2 - ab + b^2)\). So after substitution, the formula becomes \((x + 3)(x^2 - 3x + 9)\).
3Step 3: Final Answer
Thus, the factorized form of \(x^3 + 27\) using the formula for the sum of two cubes is \((x + 3)(x^2 - 3x + 9)\).
Other exercises in this chapter
Problem 56
Simplify each exponential expression. $$ \left(10 x^{2}\right)^{-3} $$
View solution Problem 57
add or subtract as indicated. $$ \frac{4 x^{2}+x-6}{x^{2}+3 x+2}-\frac{3 x}{x+1}+\frac{5}{x+2} $$
View solution Problem 57
In Exercises 15–58, find each product. $$ (3 x-4)^{3} $$
View solution Problem 57
Rewrite each expression without absolute value bars. $$\frac{-3}{|-3|}$$
View solution