Problem 57
Question
Factor the expression completely. $$ (a+b)^{2}-(a-b)^{2} $$
Step-by-Step Solution
Verified Answer
The expression factors to \(4ab\).
1Step 1: Recognize the Difference of Squares Formula
The expression \((a+b)^{2}-(a-b)^{2}\) resembles the difference of squares formula, which is \(x^2 - y^2 = (x-y)(x+y)\). The terms \((a+b)^2\) and \((a-b)^2\) are perfect squares.
2Step 2: Identify X and Y
Let \(x = (a+b)\) and \(y = (a-b)\). So the expression \((a+b)^{2}-(a-b)^{2}\) becomes \(x^2 - y^2\).
3Step 3: Apply the Difference of Squares Formula
Use the formula \(x^2 - y^2 = (x-y)(x+y)\) and substitute \(x = (a+b)\) and \(y = (a-b)\). This results in \[((a+b)-(a-b))((a+b)+(a-b))\]
4Step 4: Simplify Each Factor
Simplify the expressions in each factor: 1. \((a+b)-(a-b)\) simplifies to \(a+b-a+b = 2b\).2. \((a+b)+(a-b)\) simplifies to \(a+b+a-b = 2a\).
5Step 5: Write the Final Factored Expression
Combine the simplified factors from Step 4 to write the factored expression: \(2b \cdot 2a = 4ab\). Therefore, the complete factored form of the given expression is \(4ab\).
Key Concepts
Factoring TechniquesAlgebraic ExpressionsSquared Binomials
Factoring Techniques
Factoring is an important technique in algebra that involves rewriting an expression as a product of its factors. It's like breaking down a number into its constituents so that it can be multiplied back to form the original number. Factoring can simplify complex expressions and solve equations efficiently.
- One common factoring technique is the **Difference of Squares**, which applies to expressions in the form of \(a^2 - b^2\). It factors down to \((a - b)(a + b)\).
- Recognizing patterns is key. In difference of squares, both terms must be perfect squares.
- Factoring requires practice to spot these patterns and apply the correct method quickly.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations. They represent mathematical relationships and can include operations such as addition, subtraction, multiplication, and division. Let's explore their components and features.
- **Variables** are symbols used to represent numbers, commonly letters like \(a\), \(b\), \(x\), or \(y\).
- **Coefficients** are numbers that multiply the variables. In \(3x\), 3 is the coefficient.
- **Terms** are the separate components of an expression, like \(a\) and \(b\) in \(a+b\).
- **Operations** show how terms are combined, using symbols like \(+\), \(-\), \(\times\), or \(\div\).
Squared Binomials
A squared binomial is an expression of the form \((a + b)^2\) or \((a - b)^2\). Expanding these expressions involves using the distributive property.
- The formula for squaring a binomial \((a + b)^2\) is \(a^2 + 2ab + b^2\). For a negative sign, \((a - b)^2\) is \(a^2 - 2ab + b^2\).
- Squaring a binomial essentially means multiplying the term by itself.
Other exercises in this chapter
Problem 57
Perform the addition or subtraction and simplify. $$ \frac{2}{x+3}-\frac{1}{x^{2}+7 x+12} $$
View solution Problem 57
\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ \frac{6 y^{3} z}{2 y z^{2}} $$
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Evaluate each expression. $$ \begin{array}{ll}{\text { (a) }|(-2) \cdot 6|} & {\text { (b) }\left|\left(-\frac{1}{3}\right)(-15)\right|}\end{array} $$
View solution Problem 57
\(49-68=\) Simplify the expression and eliminate any negative exponent(s). Assume that all letters denote positive numbers. $$ \left(8 y^{3}\right)^{-2 / 3} $$
View solution