Problem 57
Question
Explain why a matrix that does not have the same number of rows and columns cannot have a multiplicative inverse.
Step-by-Step Solution
Verified Answer
A matrix must be square in order to have an inverse because it needs to have a non-zero determinant, which can only be computed for square matrices, and it needs to be able to multiply with its inverse to form the identity matrix, which requires the number of rows of the first to equal the number of columns in the second.
1Step 1: Understand the inverse of a matrix
The inverse of a matrix A is another matrix, denoted as A^-1, such that when A is multiplied with A^-1, the result is the identity matrix. The identity matrix is a special square matrix with 1's on the diagonal and 0's elsewhere.
2Step 2: Express the requirement for an inverse matrix
For a matrix to have an inverse, it must satisfy two conditions: 1) It must be square (i.e., have the same number of rows and columns). 2) Its determinant must be non-zero. A non-square matrix will not have a determinant, and thus an inverse cannot be defined for it.
3Step 3: Connect the square requirement to multiplication
Matrix multiplication is only possible if the number of columns of the first matrix is equal to the number of rows of the second one. Hence, when attempting to multiply a matrix by its inverse to get the identity matrix (which is always square), both the original matrix and its inverse must be square matrices. Otherwise, the multiplication would not be possible.
Other exercises in this chapter
Problem 56
Describe the determinants \(D_{x}\) and \(D_{y}\) in terms of the coefficients and constants in a system of two equations in two variables.
View solution Problem 57
The figure shows the letter \(L\) in a rectangular coordinate system. (GRAPH CANNOT COPY) The figure can be represented by the matrix $$B=\left[\begin{array}{ll
View solution Problem 57
Explain how to evaluate a third-order determinant.
View solution Problem 58
The figure shows the letter \(L\) in a rectangular coordinate system. (GRAPH CANNOT COPY) The figure can be represented by the matrix $$B=\left[\begin{array}{ll
View solution