Problem 57
Question
Evaluate the integrals. \(\int 3 x^{\sqrt{3}} d x\)
Step-by-Step Solution
Verified Answer
\( \int 3x^{\sqrt{3}} \, dx = \frac{3}{\sqrt{3} + 1}x^{\sqrt{3} + 1} + C \).
1Step 1: Identify the Integral Form
The integral given is \( \int 3x^{\sqrt{3}} \, dx \). This is a power form integral, where the integrand is \( 3x^{\sqrt{3}} \). We will apply the power rule for integration to solve this.
2Step 2: Apply the Power Rule for Integration
The power rule for integration states that \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \), where \( n eq -1 \). Here \( n = \sqrt{3} \), so we integrate by adding 1 to the exponent and dividing by the new exponent.
3Step 3: Integrate the Function
Using the power rule, add 1 to the exponent: \( \sqrt{3} + 1 = \sqrt{3} + 1 \). Now divide \( x^{\sqrt{3}+1} \) by \( \sqrt{3}+1 \), integrating the function. Include the constant coefficient of 3 in the integral. Combine terms to get:\[ \int 3x^{\sqrt{3}} \ dx = \frac{3}{\sqrt{3} + 1}x^{\sqrt{3} + 1} + C \]
4Step 4: Simplify the Result
Simplifying the result: Finalize the expression:\[ \int 3x^{\sqrt{3}} \ dx = \frac{3}{\sqrt{3} + 1}x^{\sqrt{3} + 1} + C \] This is the indefinite integral of the function. The constant \( C \) is added because it represents the constant of integration in indefinite integrals.
Key Concepts
Power Rule for IntegrationIndefinite IntegralsExponents in Integrals
Power Rule for Integration
The Power Rule for Integration is a key principle when dealing with integrals of power functions. It simplifies many problems involving finding antiderivatives. The rule provides a straightforward method to integrate functions of the form \( x^n \). Here's how it works:
1. Increasing the exponent: \( \sqrt{3} + 1 \)
2. Dividing by the new exponent: \( \frac{x^{\sqrt{3}+1}}{\sqrt{3}+1} \)
3. Including \( C \) for the solution's completeness. This makes the power rule a powerful and essential tool in calculus, especially for indefinite integrals.
- Consider a function \( x^n \). To integrate it, increase the exponent by one, turning \( n \) into \( n+1 \).
- Divide by the new exponent \( n+1 \), resulting in \( \frac{x^{n+1}}{n+1} \).
- Don't forget to add the constant of integration \( C \). This ensures that all potential antiderivatives are considered.
1. Increasing the exponent: \( \sqrt{3} + 1 \)
2. Dividing by the new exponent: \( \frac{x^{\sqrt{3}+1}}{\sqrt{3}+1} \)
3. Including \( C \) for the solution's completeness. This makes the power rule a powerful and essential tool in calculus, especially for indefinite integrals.
Indefinite Integrals
Indefinite integrals represent a family of functions and are central in calculus. They are also known as antiderivatives. When you compute an indefinite integral, you're finding a function whose derivative equals the integrand.
Unlike definite integrals, indefinite integrals do not have upper and lower bounds. Instead, they account for all possible antiderivatives by adding a constant \( C \). This is often called the 'constant of integration.'
Indefinite integrals are essential in solving problems involving:
Unlike definite integrals, indefinite integrals do not have upper and lower bounds. Instead, they account for all possible antiderivatives by adding a constant \( C \). This is often called the 'constant of integration.'
Indefinite integrals are essential in solving problems involving:
- Motion
- Area calculations
- Other physical and mathematical applications
- The result must include a constant \( C \) since any constant derivative is zero.
- This means a family of functions can each serve as a solution.
Exponents in Integrals
Exponents in integrals can change the approach to finding an antiderivative. Typical integrals involve constant exponents, but you can encounter fractional or irrational exponents as well. These require careful application of integration rules.
What happens when exponents are involved in integration?
What happens when exponents are involved in integration?
- Normal rules apply: use the Power Rule for Integration.
- Adjust the exponent during integration by incrementing it by 1.
- Divide by this adjusted exponent to correctly balance the formula.
- The integration step involves adding 1 to \( \sqrt{3} \) and dividing by this sum.
- The challenge comes in calculating new expressions like \( \sqrt{3} + 1 \) precisely.
- Despite the complexity, the approach remains consistent whether dealing with simple integers, fractions, or more exotic exponents.
Other exercises in this chapter
Problem 57
In Exercises \(49-70\) , find the derivative of \(y\) with respect to the appropriate variable. $$ y=\sec ^{-1} \frac{1}{t}, \quad 0
View solution Problem 57
In Exercises \(55-68,\) use logarithmic differentiation to find the derivative of \(y\) with respect to the given independent variable. $$ y=\sqrt{\frac{t}{t+1}
View solution Problem 57
In Exercises \(53-60,\) you will explore some functions and their inverses together with their derivatives and linear approximating functions at specified point
View solution Problem 58
Evaluate the integrals in Exercises \(51-60 .\) $$ \int_{1}^{4} \frac{8 \cosh \sqrt{x}}{\sqrt{x}} d x $$
View solution