Problem 57
Question
Evaluate the expression for the given value of the variable(s). $$x^{2}-12 when x=6$$
Step-by-Step Solution
Verified Answer
The evaluated value of the expression is 24
1Step 1: Substitute the given value
Replace the \(x\) in the equation \(x^{2} - 12\) with the value 6. This results in \(6^{2} - 12\)
2Step 2: Calculate the squared term
Squaring the value 6 gives 36. The expression then becomes \(36 - 12\)
3Step 3: Perform the subtraction
Subtract 12 from 36. The value obtained is 24
Key Concepts
SubstitutionEvaluationSquaringSubtraction
Substitution
Substitution is a crucial concept in algebra, as it allows us to replace variables in an expression with specific values. In the given problem, we are asked to replace the variable \( x \) with \( 6 \). The expression originally is \( x^2 - 12 \). By substituting \( x \) with \( 6 \), the expression becomes \( 6^2 - 12 \). A few steps to remember during substitution:
- Identify the variable you need to substitute.
- Replace the variable with the given numerical value.
- Rewrite the complete expression with your substitution.
Evaluation
Evaluation involves finding the numerical value of an algebraic expression once substitution is complete. After substituting \( x \) with \( 6 \), the expression becomes \( 6^2 - 12 \). To evaluate:
- First, simplify each part of the substituted expression as much as possible.
- In our example, begin by squaring \( 6 \) to evaluate \( 6^2 \).
- Then proceed to perform any additional arithmetic operations.
Squaring
The squaring operation is a fundamental aspect of algebra that involves multiplying a number by itself. In the expression \( 6^2 - 12 \), squaring is our first operation post-substitution. To square a number:
- Multiply the number by itself: for \( 6^2 \), compute \( 6 \times 6 \).
- This results in \( 36 \).
Subtraction
Subtraction is the final arithmetic operation needed to evaluate our current expression. After we square \( 6 \) to get \( 36 \), we are left with the expression \( 36 - 12 \). To perform the subtraction:
- Take the result of the squared term and subtract \( 12 \) from it.
- In this case, compute \( 36 - 12 \), which equals \( 24 \).
Other exercises in this chapter
Problem 56
Simplify the expression. \(\left(6 z^{4}\right)^{2} \cdot z^{3}\)
View solution Problem 57
Rewrite the expression with positive exponents. $$ \frac{y^{4}}{x^{-10}} $$
View solution Problem 57
Simplify the expression. Use only positive exponents. $$ \frac{4 x y}{2 x^{-1} y^{-3}} \cdot\left(\frac{2 x y^{2}}{3 x y}\right)^{-2} $$
View solution Problem 57
Write the expression as a single power of the base. (Lesson 8.1) $$r^{2} \cdot r^{4}$$
View solution