Problem 57
Question
Evaluate each piece wise function at the given values of the independent variable. \(h(x)=\left\\{\begin{array}{ccc}\frac{x^{2}-9}{x-3} & \text { if } & x \neq 3 \\\ 6 & \text { if } & x=3\end{array}\right.\) a. \(h(5)\) b. \(h(0)\) c. \(h(3)\)
Step-by-Step Solution
Verified Answer
Based on the steps and calculations, the answers are \( h(5) = 8 \), \( h(0) = 3 \), and \( h(3) = 6 \).
1Step 1: Evaluation of \( h(5) \)
The value 5 is not equal to 3, so the first part of the piecewise function applies. The expression should be evaluated as \( h(5) = \frac{5^2 - 9}{5 - 3} = \frac{16}{2} = 8. \)
2Step 2: Evaluation of \( h(0) \)
The value 0 also does not equal to 3, so again, the first part of the piecewise function should be used. This gives \( h(0) = \frac{0^2 - 9}{0 - 3} = \frac{-9}{-3} = 3. \)
3Step 3: Evaluation of \( h(3) \)
In this case, the value 3 equals 3. Therefore, the second part of the piecewise function applies. This means \( h(3) \) equals to 6.
Key Concepts
Function EvaluationIndependent VariablePrecalculus Problem Solving
Function Evaluation
Function evaluation involves determining the output of a function for a given input value, which is the independent variable. In simpler terms, if you have a function, you want to know what result you get when you plug a specific value into it. In the case of piecewise functions, this can be a bit tricky because the function is defined by different expressions depending on the input value.
- For example, look at the function \( h(x) \) provided in the exercise. It's composed of two different expressions: \( \frac{x^2 - 9}{x - 3} \) and a constant \( 6 \).
- The expression to use depends on whether \( x \) (the input or independent variable) equals 3 or not.
Independent Variable
The independent variable is the input or the variable we choose values for in a function. In the function \( h(x) \), \( x \) is the independent variable. You provide different values to \( x \), and the function returns a result for each of these inputs, known as the dependent variable.
- In mathematical terms, if the function is expressed as \( h(x) \), then \( x \) is the independent variable.
- Each function may have specific rules or conditions for different values of the independent variable, as seen in piecewise functions.
Precalculus Problem Solving
Precalculus problem solving often involves dealing with different types of functions, including piecewise functions. This requires an understanding of how to approach evaluating different conditions or parts of a function based on its definition and the values of the independent variable.
- The exercise is an excellent example of this, demonstrating the evaluation of a piecewise function through several distinct scenarios.
- You need to match the value of the independent variable with the appropriate condition or equation described in the piecewise function.
- Identify the function's expression that matches your input condition.
- Substitute the input value into the correct expression and solve for the output.
Other exercises in this chapter
Problem 56
Graph equation in a rectangular coordinate system. $$f(x)=3$$
View solution Problem 57
Complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$x^{2}+y^{2}+8 x-2 y-8=0$$
View solution Problem 57
\(f\) and \(g\) are defined by the following tables. Use the tables to evaluate each composite function. $$\begin{array}{cccc} \hline x & f(x) & x & g(x) \\ \hl
View solution Problem 57
Find. a. \((f \circ g)(x)\) b. \((g \circ f)(x)\) c. \((f \circ g)(2)\) d. \((g \circ f)(2)\) $$f(x)=x^{2}+2, g(x)=x^{2}-2$$
View solution