Problem 57
Question
Begin by graphing the standard quadratic function, \(f(x)=x^{2} .\) Then use transformations of this graph to graph the given function. $$h(x)=-(x-2)^{2}$$
Step-by-Step Solution
Verified Answer
The function \(h(x) = -(x-2)^{2}\) presents as a parabola shifted 2 units to the right, compared to \(f(x) = x^{2}\), and is reflected over the x-axis.
1Step 1: Understanding the Base Function
The standard quadratic function is \(f(x) = x^2\). Its graph is a parabola that opens upwards with the vertex at the origin (0,0).
2Step 2: Applying the Shift
The function \(h(x) = -(x-2)^{2}\) is the basic quadratic function shifted 2 units to the right. You achieve this shift by replacing every \(x\) in the original function with \((x - 2)\). Now the vertex of the parabola is at (2, 0).
3Step 3: Applying the Reflection
The negative sign in front of the square implies a reflection about the X-axis. This means that the parabola, which opened upwards in the original function, now opens downwards.
4Step 4: Drawing the Transformed Function
Based on the transformations outlined in the previous steps, draw the transformed graph. Start at the vertex (2, 0) and draw a parabola opening downward.
Other exercises in this chapter
Problem 57
find and simplify the difference quotient $$ \frac{f(x+h)-f(x)}{h}, h \neq 0 $$ for the given function. $$ f(x)=3 x+7 $$
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Find a. \((f \circ g)(x) \quad \) b. \((g \circ f)(x) \quad \) c. \((f \circ g)(2) \quad \) d. \((g \circ f)(2)\) $$f(x)=x^{2}+2, g(x)=x^{2}-2$$
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Graph each equation in a rectangular coordinate system. $$3 x-18=0$$
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complete the square and write the equation in standard form. Then give the center and radius of each circle and graph the equation. $$ x^{2}+y^{2}+12 x-6 y-4=0
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