Problem 57
Question
(a) What is the average kinetic energy per molecule of a monatomic gas at a temperature of \(25^{\circ} \mathrm{C} ?\) (b) What is the rms speed of the molecules if the gas is helium? (A helium molecule consists of a single atom of mass \(6.65 \times 10^{-27} \mathrm{~kg}\).
Step-by-Step Solution
Verified Answer
(a) \(6.17 \times 10^{-21}\) J; (b) 1253 m/s.
1Step 1: Convert Temperature to Kelvin
First, convert the given temperature from Celsius to Kelvin. The formula to convert is: \( T(K) = T(^{\circ}C) + 273.15 \). For 25°C, \( T = 25 + 273.15 = 298.15 \) K.
2Step 2: Calculate Average Kinetic Energy
Use the formula for average kinetic energy per molecule of a monatomic gas: \( KE_{avg} = \frac{3}{2} k T \) where \( k = 1.38 \times 10^{-23} \, \text{J/K} \). Substituting the values gives: \( KE_{avg} = \frac{3}{2} \times 1.38 \times 10^{-23} \times 298.15 \approx 6.17 \times 10^{-21} \) J.
3Step 3: Calculate RMS Speed
The formula for the root-mean-square (rms) speed of gas molecules is \( v_{rms} = \sqrt{\frac{3kT}{m}} \). Substituting the known values, \( k = 1.38 \times 10^{-23} \, \text{J/K} \), \( T = 298.15 \) K, and \( m = 6.65 \times 10^{-27} \, \text{kg} \), the calculation is: \( v_{rms} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 298.15}{6.65 \times 10^{-27}}} \approx 1253 \) m/s.
Key Concepts
Monatomic GasRMS SpeedTemperature ConversionHelium Molecules
Monatomic Gas
A monatomic gas consists of individual atoms that are not bound to each other.
This means in a monatomic gas, each molecule is made up of a single atom. Examples include helium, neon, and argon.
When dealing with gases like helium, it’s important to understand that they have some distinct characteristics:
- They exert pressure through countless collisions against the walls of their container.
- Despite being a single type of atom, they follow the ideal gas laws well under many conditions.
- The behavior of monatomic gases is simpler to model than that of polyatomic gases due to the absence of intermolecular forces.
RMS Speed
The root-mean-square (rms) speed of gas molecules provides a measure of how fast the molecules are moving in a gas sample. It is critical in understanding the kinetic theory of gases, where:
- RMS speed (\(v_{rms}\)) connects directly to the temperature and molecular mass of the gas.
- It gives insight into gas properties like diffusion rates and pressure exerted by the gas.
Temperature Conversion
Temperature in scientific contexts is often measured in Kelvin rather than Celsius. Kelvin is the SI unit for temperature and is essential for calculations involving physical properties:
- Conversion from Celsius to Kelvin requires adding 273.15 to the Celsius temperature.
- This conversion ensures temperatures are always positive, simplifying the math involved.
Helium Molecules
Helium is a noble gas, and its molecules are unique in that they are monatomic. Each helium molecule is comprised simply of a single helium atom.Some specific properties relevant to helium in gas behavior are:
- Each helium atom has a mass of \(6.65 \times 10^{-27}\) kg.
- Helium is inert, meaning it doesn't easily react with other substances.
Other exercises in this chapter
Problem 54
What is the average kinetic energy per molecule in a monatomic gas at (a) \(10^{\circ} \mathrm{C}\) and (b) \(90^{\circ} \mathrm{C} ?\)
View solution Problem 56
What is the rms speed of the molecules in low-density oxygen gas at \(0^{\circ} \mathrm{C} ?\) (The mass of an oxygen molecule, \(\mathrm{O}_{2},\) is \(\left.5
View solution Problem 59
A quantity of an ideal gas is at \(0^{\circ} \mathrm{C}\). An equal quantity of another ideal gas is at twice the absolute temperature. What is its Celsius temp
View solution Problem 60
A sample of oxygen \(\left(\mathrm{O}_{2}\right)\) and another sample of nitrogen \(\left(\mathrm{N}_{2}\right)\) are at the same temperature. (a) The rms speed
View solution