Problem 57
Question
A classmate says, "A weak-field ligand usually means the complex is high spin." Is your classmate correct? Explain.
Step-by-Step Solution
Verified Answer
Yes, your classmate is correct. A weak-field ligand results in a smaller crystal field splitting energy (Δ), which is more likely to lead to a high-spin complex. This is because when Δ is smaller than the pairing energy (P), electrons prefer to occupy higher-energy orbitals with parallel spins rather than pairing up in lower-energy orbitals.
1Step 1: Understanding Weak-Field Ligands and High-Spin Complexes
Weak-field ligands are ligands that do not produce a large crystal field splitting energy (Δ). They result in smaller differences between the energy levels of the d orbitals in a transition metal complex. This means that d electrons will not be strongly stabilized by the ligand, and the ligand has a weaker ability to create a field around the metal ion.
On the other hand, high-spin complexes are those in which electrons prefer to occupy higher-energy orbitals with parallel spins, rather than pairing up in lower-energy orbitals. This occurs when the crystal field splitting energy (Δ) is smaller than the pairing energy (P), which is the energy required for an electron to pair up in a lower-energy orbital (Δ < P).
2Step 2: Examining the Correlation between Weak-Field Ligands and High-Spin Complexes
A weak-field ligand, as mentioned earlier, results in a smaller crystal field splitting energy (Δ). When the splitting energy is small, it is more likely that the complex will be high-spin because the electrons would prefer occupying the higher-energy orbitals with parallel spins rather than pairing up in the lower-energy orbitals.
In other words, if the ligands are weak-field, the electrons will not be stabilized by their interaction with the ligands, so they will require less energy to move to the next energy level (as compared to moving to a higher orbit in a strong-field complex). Thus, it's more probable that the complex will be high-spin with weak-field ligands.
3Step 3: Conclusion
Based on this explanation, it can be said that the classmate's statement is indeed correct. A weak-field ligand usually means the complex will be high-spin, given that the crystal field splitting energy is smaller than the pairing energy, making it more favorable for electrons to occupy higher-energy orbitals with parallel spins.
Other exercises in this chapter
Problem 55
Give the number of (valence) \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{TiCl}_{
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Give the number of (valence) \(d\) electrons associated with the central metal ion in each of the following complexes: (a) \(\mathrm{K}_{3}\left[\mathrm{Fe}(\ma
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A classmate says, "A strong-field ligand means that the ligand binds strongly to the metal ion." Is your classmate correct? Explain.
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For each of the following metals, write the electronic configu- ration of the atom and its \(2+\) ion: \((\) a) \(M n,\) (b) \(R u,\) (c) \(R h\). Draw the crys
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