Problem 56
Question
Write the first five terms of the sequence defined recursively. $$a_{1}=32, a_{k+1}=\frac{1}{2} a_{k}$$
Step-by-Step Solution
Verified Answer
The first five terms of the sequence are 32, 16, 8, 4, 2.
1Step 1: First Term
The first term \(a_{1}\) is given as 32. So, the first term is 32.
2Step 2: Second Term
Apply the recursive rule to get the second term: \(a_{2}=\frac{1}{2} a_{1}= \frac{1}{2} \times 32 = 16\). So, the second term is 16.
3Step 3: Third Term
Again apply the recursive rule to get the third term: \(a_{3}=\frac{1}{2} a_{2}=\frac{1}{2} \times 16 = 8\). So, the third term is 8.
4Step 4: Fourth Term
Apply the recursive rule to get the fourth term: \(a_{4}=\frac{1}{2} a_{3}=\frac{1}{2} \times 8 = 4\). So, the fourth term is 4.
5Step 5: Fifth Term
For the last time apply the recursive rule to get the fifth term: \(a_{5}=\frac{1}{2} a_{4}=\frac{1}{2} \times 4 = 2\). So, the fifth term is 2.
Key Concepts
Sequence DefinitionArithmetic SequencesGeometric Sequences
Sequence Definition
Imagine a lineup of objects where the arrangement follows a specific pattern; this is essentially what we mean by a sequence in mathematics. It's a collection of numbers that are related to each other according to some rule. This rule may be straightforward, such as adding the same number to move from one term in the sequence to the next, or it may be more complex.
To put it simply, think of each number in a sequence as an individual player on a sports team. They each have their position, which in a sequence is determined by an index, often denoted with subscripts like this: \( a_1, a_2, a_3, ... \). The position tells us the order of the players, just like the numbering on a sports team's roster.
Now, when we talk about defining a sequence recursively, it's like saying you can figure out any player's capabilities by looking at the previous player's performance. The initial player's performance is a given, which in mathematics we call the 'first term' or 'initial value,' and each subsequent player improves (or changes) based on the rule applied to the player that came before.
To put it simply, think of each number in a sequence as an individual player on a sports team. They each have their position, which in a sequence is determined by an index, often denoted with subscripts like this: \( a_1, a_2, a_3, ... \). The position tells us the order of the players, just like the numbering on a sports team's roster.
Now, when we talk about defining a sequence recursively, it's like saying you can figure out any player's capabilities by looking at the previous player's performance. The initial player's performance is a given, which in mathematics we call the 'first term' or 'initial value,' and each subsequent player improves (or changes) based on the rule applied to the player that came before.
Arithmetic Sequences
An arithmetic sequence is one of the simplest types of sequences in math. It's like climbing stairs where each step up is the same height as the last one. In numerical terms, it means that we start with a number, known as the initial term, and then consistently add (or subtract) the same value, which we call the common difference, to get the next term in the sequence.
For instance, if you start on the fifth step (our initial term), and each step is 2 inches tall (our common difference), the height you reach with every move will be your current height plus 2 inches. Here's how that looks with numbers, given starting with 5: \(a_1 = 5, a_2 = 7, a_3 = 9, \) and so on. Each term is determined by the formula \( a_n = a_1 + (n-1) \cdot d \), where \( d \) is the common difference, and \( n \) refers to the nth term in the sequence.
For instance, if you start on the fifth step (our initial term), and each step is 2 inches tall (our common difference), the height you reach with every move will be your current height plus 2 inches. Here's how that looks with numbers, given starting with 5: \(a_1 = 5, a_2 = 7, a_3 = 9, \) and so on. Each term is determined by the formula \( a_n = a_1 + (n-1) \cdot d \), where \( d \) is the common difference, and \( n \) refers to the nth term in the sequence.
Geometric Sequences
Now let's get a bit more adventurous and think of a sequence as a series of bounces on a trampoline: each bounce might be a fraction of the last, but it's always a proportional change. In mathematical terms, this is a geometric sequence, where instead of adding a constant value, we multiply by a fixed number known as the common ratio.
If your first bounce is, say, 100cm high, and each subsequent bounce is half as high as the one before, your bounces form a geometric sequence. The height of each bounce can be calculated by the formula \( a_n = a_1 \cdot r^{(n-1)} \), where \( a_1 \) is the first term and \( r \) is the common ratio. In this case: 100cm, 50cm, 25cm, as each bounce is \(\frac{1}{2}\) of the previous one. This is closely linked to our example from the original exercise, where we see a recursive sequence with \(a_{k+1} = \frac{1}{2}a_k\), implying that the common ratio is \(\frac{1}{2}\).
If your first bounce is, say, 100cm high, and each subsequent bounce is half as high as the one before, your bounces form a geometric sequence. The height of each bounce can be calculated by the formula \( a_n = a_1 \cdot r^{(n-1)} \), where \( a_1 \) is the first term and \( r \) is the common ratio. In this case: 100cm, 50cm, 25cm, as each bounce is \(\frac{1}{2}\) of the previous one. This is closely linked to our example from the original exercise, where we see a recursive sequence with \(a_{k+1} = \frac{1}{2}a_k\), implying that the common ratio is \(\frac{1}{2}\).
Other exercises in this chapter
Problem 55
Finding the Sum of a Finite Geometric Sequence Find the sum. Use a graphing utility to verify your result. $$\sum_{n=1}^{9} 2^{n-1}$$
View solution Problem 55
Find the specified \(n\) th term in the expansion of the binomial. \((x+8)^{10}, n=4\)
View solution Problem 56
Use the table feature of a graphing utility to find the first 10 terms of the sequence. (Assume \(n\) begins with 1.) $$a_{n}=8-12.5 n$$
View solution Problem 56
Evaluate \(_{n} C_{r}\) using the formula from this section. $$_{20} C_{0}$$
View solution