Problem 56
Question
What is the hydronium ion concentration of a \(1.2 \times 10^{-4} \mathrm{M}\) solution of \(\mathrm{HClO}_{4} ?\) What is its \(\mathrm{pH}\) ?
Step-by-Step Solution
Verified Answer
The hydronium ion concentration is \\(1.2 \times 10^{-4} \, \mathrm{M}\\) and the \\(\mathrm{pH}\\) is approximately 3.92.
1Step 1: Understand the acid's dissociation
Perchloric acid \(\mathrm{HClO}_4\) is a strong acid. This means it completely dissociates in water. The equation for its dissociation is: \[\mathrm{HClO}_{4(aq)} \rightarrow \mathrm{H}^{+}_{(aq)} + \mathrm{ClO}_{4}^{-}_{(aq)}\] Since it dissociates completely, the concentration of hydronium ions \(\mathrm{H}^{+}\) will be equal to the initial concentration of the acid.
2Step 2: Calculate the hydronium ion concentration
The concentration of hydronium ions \(\left[\mathrm{H}^{+}\right]\) is equal to the concentration of the \(\mathrm{HClO}_4\) solution since it dissociates completely. Thus, \[\left[\mathrm{H}^{+}\right] = 1.2 \times 10^{-4} \, \mathrm{M}\]
3Step 3: Use the hydronium concentration to find the pH
The \(\mathrm{pH}\) of a solution is calculated using the negative logarithm (base 10) of the hydronium ion concentration: \[\mathrm{pH} = -\log\left([\mathrm{H}^{+}]\right)\] Substituting in the given value: \[\mathrm{pH} = -\log\left(1.2 \times 10^{-4}\right)\] Using a calculator, this gives a \(\mathrm{pH}\) of approximately 3.92.
Key Concepts
Perchloric AcidAcid DissociationpH Calculation
Perchloric Acid
Perchloric acid, commonly represented by the formula \(\mathrm{HClO}_4\), is known for being a strong acid. This means that when it is added to water, it dissociates completely into its constituent ions.
This dissociation can be expressed with the chemical equation:
Because of this characteristic, we can easily determine the concentration of hydronium ions in a solution if we know the initial concentration of the acid.
This dissociation can be expressed with the chemical equation:
- \(\mathrm{HClO}_{4(aq)} \rightarrow \mathrm{H}^{+}_{(aq)} + \mathrm{ClO}_{4}^{-}_{(aq)}\)
Because of this characteristic, we can easily determine the concentration of hydronium ions in a solution if we know the initial concentration of the acid.
Acid Dissociation
Acid dissociation refers to the process where an acid breaks down in water to form its constituent ions. In strong acids like perchloric acid, this process is complete.
For weak acids, this is not the case, as they only partially dissociate, leading to an equilibrium between the un-dissociated molecules and the ions.
With strong acids, since dissociation is complete, the concentration of hydrogen ions \([\mathrm{H}^+]\) in the solution is equal to the initial concentration of the acid introduced.
For weak acids, this is not the case, as they only partially dissociate, leading to an equilibrium between the un-dissociated molecules and the ions.
With strong acids, since dissociation is complete, the concentration of hydrogen ions \([\mathrm{H}^+]\) in the solution is equal to the initial concentration of the acid introduced.
- For example, if you started with a \( 1.2 \times 10^{-4} \mathrm{M} \) solution of \( \mathrm{HClO}_4\), the \([\mathrm{H}^+]\) after dissociation is also \( 1.2 \times 10^{-4} \mathrm{M} \).
pH Calculation
The pH of a solution is a measure of its acidity or alkalinity. To find the pH of a solution, you use the formula:
Hence, a lower pH value signifies a higher concentration of \([\mathrm{H}^+]\) ions, which means greater acidity. For example, with a \( 1.2 \times 10^{-4} \mathrm{M} \) \( \mathrm{HClO}_4\) solution, the pH is calculated using the given concentration:
This demonstrates that the solution is acidic, as expected from a strong acid. Understanding this calculation is crucial for students as pH is a fundamental concept in chemistry.
- \(\mathrm{pH} = -\log([\mathrm{H}^+])\)
Hence, a lower pH value signifies a higher concentration of \([\mathrm{H}^+]\) ions, which means greater acidity. For example, with a \( 1.2 \times 10^{-4} \mathrm{M} \) \( \mathrm{HClO}_4\) solution, the pH is calculated using the given concentration:
- \(\mathrm{pH} = -\log(1.2 \times 10^{-4})\)
This demonstrates that the solution is acidic, as expected from a strong acid. Understanding this calculation is crucial for students as pH is a fundamental concept in chemistry.
Other exercises in this chapter
Problem 53
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