Problem 56
Question
Use a graphing calculator to evaluate the sum. \(\sum_{k=1}^{100}(3 k+4)\)
Step-by-Step Solution
Verified Answer
The sum is 15550.
1Step 1: Understanding the Summation
The given expression is a summation, represented as \( \sum_{k=1}^{100}(3k+4) \). It means you need to calculate the sum of the expression \( 3k+4 \) for each integer value of \( k \) from 1 to 100.
2Step 2: Identify the Formula to Use
Notice that the expression inside the summation has a form \( ax+b \). Here, \( a = 3 \) and \( b = 4 \). You can split the summation into separate sums: \[ \sum_{k=1}^{100}(3k+4) = \sum_{k=1}^{100}3k + \sum_{k=1}^{100}4 \] This allows us to evaluate each part individually.
3Step 3: Calculate the Sum of Linear Term
First, calculate \( \sum_{k=1}^{100}3k \). The sum of the first \( n \) integers is \( \frac{n(n+1)}{2} \). Applying this for 3 times each integer:\[ \sum_{k=1}^{100}3k = 3 \times \frac{100(100+1)}{2} = 3 \times 5050 = 15150 \]
4Step 4: Calculate the Sum of Constant Term
Next, calculate the sum of the constant term \( \sum_{k=1}^{100}4 \). Since 4 is constant and added 100 times:\[ \sum_{k=1}^{100}4 = 4 \times 100 = 400 \]
5Step 5: Combine the Results
Now, add the results from Steps 3 and 4:\[ \sum_{k=1}^{100}(3k+4) = 15150 + 400 = 15550 \]
Key Concepts
graphing calculatorlinear expressionsum of integersconstant term
graphing calculator
A graphing calculator is a powerful tool in mathematics, designed to plot graphs and solve equations with ease. When dealing with summation problems such as \( \sum_{k=1}^{100}(3k+4) \), a graphing calculator can simplify the process significantly. Instead of manually calculating each term, a graphing calculator can automate this process.
Graphing calculators have specific functions that allow users to input summation expressions. With the proper syntax, these calculators can compute the entire sum efficiently. To do this, you typically access the summation function in the calculator's menu, input your expression such as \( 3k+4 \), and specify the range from 1 to 100.
Using a graphing calculator to evaluate summations saves time and reduces errors. It is especially useful for complex or lengthy expressions, where hand calculations would be prone to mistakes.
Graphing calculators have specific functions that allow users to input summation expressions. With the proper syntax, these calculators can compute the entire sum efficiently. To do this, you typically access the summation function in the calculator's menu, input your expression such as \( 3k+4 \), and specify the range from 1 to 100.
Using a graphing calculator to evaluate summations saves time and reduces errors. It is especially useful for complex or lengthy expressions, where hand calculations would be prone to mistakes.
linear expression
A linear expression is a mathematical expression involving variables raised to the power of one. These expressions have the general form \( ax + b \), where \( a \) and \( b \) are constants. In the context of the summation \( \sum_{k=1}^{100}(3k+4) \), the linear expression is \( 3k + 4 \).
Linear expressions like \( 3k + 4 \) are composed of a variable term, in this case represented by \( 3k \), and a constant term, \( 4 \).
Linear expressions like \( 3k + 4 \) are composed of a variable term, in this case represented by \( 3k \), and a constant term, \( 4 \).
- The coefficient \( 3 \) indicates how much \( k \) is scaled.
- The constant term \( 4 \) implies that each value of the linear term \( 3k \) is adjusted by adding 4.
sum of integers
Calculating the sum of integers is a common mathematical operation and involves adding a series of sequential whole numbers. For instance, when tackling \( \sum_{k=1}^{100} k \), you're calculating the sum of integers from 1 to 100.
The formula for the sum of the first \( n \) integers is \( \frac{n(n+1)}{2} \). Applying this formula simplifies the calculation. In the example with our summation problem \( \sum_{k=1}^{100} 3k \), each integer is multiplied by 3, a scaling factor, before summing.
Therefore, the process becomes:
The formula for the sum of the first \( n \) integers is \( \frac{n(n+1)}{2} \). Applying this formula simplifies the calculation. In the example with our summation problem \( \sum_{k=1}^{100} 3k \), each integer is multiplied by 3, a scaling factor, before summing.
Therefore, the process becomes:
- Determine the sum of integers using the formula.
- Multiply that sum by the scaling factor, 3 in this case.
constant term
A constant term in mathematics is a number on its own, or in other words, a term in an algebraic expression that does not change with the variable. In the expression \( 3k+4 \), the constant term is 4.
When evaluating summations like \( \sum_{k=1}^{100}(3k+4) \), it's important to isolate and sum the constant terms individually. Since the constant 4 appears for every value of \( k \) from 1 to 100, the sum of these constant terms is calculated by multiplying the constant by the number of times it appears:
When evaluating summations like \( \sum_{k=1}^{100}(3k+4) \), it's important to isolate and sum the constant terms individually. Since the constant 4 appears for every value of \( k \) from 1 to 100, the sum of these constant terms is calculated by multiplying the constant by the number of times it appears:
- Given the expression \( 4 \) and that \( k \) ranges from 1 to 100, you calculate \( 4 \times 100 \).
- This results in \( 400 \), contributing to the overall summation.
Other exercises in this chapter
Problem 56
Find the partial \(\operatorname{sum} S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$a_{2}=8, \quad a_{5}=9.5, \quad n=15$$
View solution Problem 56
The probability that an archer hits the target is \(p=0.9,\) so the probability that he misses the target is \(q=0.1 .\) It is known that in this situation the
View solution Problem 57
A partial sum of an arithmetic sequence is given. Find the sum. $$1+5+9+\dots+401$$
View solution Problem 57
Which is larger, \((100 !)^{101}\) or (101!) \(^{100}\) ? [ Hint: Try factoring the expressions. Do they have any common factors?]
View solution