Problem 56
Question
Two radioactive elements A and B have decay constant \(\lambda\) and \(10 \lambda\) respectively. If the decay begins with the same number of atoms of the \(\mathrm{n}\), the ratio of atoms of \(\mathrm{A}\) to those of B after time \(1 / 9 \lambda\) will be (a) \(\mathrm{e}^{-3}\) (b) \(\mathrm{e}^{2}\) (c) \(\mathrm{e}\) (d) \(\mathrm{e}^{-1}\)
Step-by-Step Solution
Verified Answer
The ratio of atoms of A to B is \( e \), so the answer is (c) \( e \).
1Step 1: Understanding Decay Law
The radioactive decay law states that the number of atoms decaying per unit time is proportional to the current number of atoms. Mathematically, this is represented as \( N(t) = N_0 e^{-\lambda t} \), where \( N(t) \) is the number of atoms at time \( t \), \( N_0 \) is the initial number of atoms, and \( \lambda \) is the decay constant.
2Step 2: Apply Decay Law to Element A
For element A, the decay constant is \( \lambda \). Using the decay law, the number of atoms of element A at time \( t = \frac{1}{9\lambda} \) is \( N_A = N_0 e^{-\lambda \cdot \frac{1}{9\lambda}} = N_0 e^{-rac{1}{9}} \).
3Step 3: Apply Decay Law to Element B
For element B, the decay constant is \( 10\lambda \). Similarly, the number of atoms of element B at time \( t = \frac{1}{9\lambda} \) is \( N_B = N_0 e^{-10\lambda \cdot \frac{1}{9\lambda}} = N_0 e^{-rac{10}{9}} \).
4Step 4: Calculate the Ratio
To find the ratio of atoms of A to atoms of B after the given time, divide the expressions obtained in Step 2 and Step 3. The ratio is \( \frac{N_A}{N_B} = \frac{N_0 e^{-rac{1}{9}}}{N_0 e^{-rac{10}{9}}} = e^{-rac{1}{9} + \frac{10}{9}} = e^{\frac{9}{9}} = e \).
Key Concepts
Decay ConstantRadioactive Decay LawAtoms Ratio Calculation
Decay Constant
In radioactive decay, a vital concept is the decay constant, symbolized as \( \lambda \). It expresses how quickly a radioactive substance transforms into another element or isotope. The decay constant is the proportionality factor in the formula that represents how many atoms disintegrate per unit time. It reflects the intrinsic ability of the substance to undergo decay and is unique to each radioisotope.
For example, if a substance has a high decay constant, it means it decays rapidly. Conversely, a low decay constant indicates slower decay.
This principle can be easily viewed mathematically in the radioactive decay law, where the decay constant directly influences the exponential function that represents the decay process. Understanding the decay constant is crucial for predicting how much of a radioisotope will remain after a certain period.
For example, if a substance has a high decay constant, it means it decays rapidly. Conversely, a low decay constant indicates slower decay.
This principle can be easily viewed mathematically in the radioactive decay law, where the decay constant directly influences the exponential function that represents the decay process. Understanding the decay constant is crucial for predicting how much of a radioisotope will remain after a certain period.
Radioactive Decay Law
The radioactive decay law formulates the process of radioactive transformation mathematically and helps us predict the remaining quantity of a substance over time. The law is represented by the equation: \( N(t) = N_0 e^{-\lambda t} \).
Here:
In essence, the radioactive decay law gives a comprehensive view of how and at what rate a radioactive substance breaks down over a period, dictating how quickly it becomes stable or transforms into another isotope.
Here:
- \(N(t)\) is the number of atoms left at time \(t\).
- \(N_0\) is the initial quantity of the substance at time zero.
- \(\lambda\) is the decay constant.
- \(t\) is the time elapsed.
In essence, the radioactive decay law gives a comprehensive view of how and at what rate a radioactive substance breaks down over a period, dictating how quickly it becomes stable or transforms into another isotope.
Atoms Ratio Calculation
Calculating the ratio of the number of atoms after a given time between two radioactive substances involves using the decay law for each substance and comparing them. For two substances, A and B, each with different decay constants, it becomes necessary to input their values into the decay equation.
Suppose we take two elements, A and B, with decay constants \(\lambda\) and \(10\lambda\) respectively. After a specific time, \(t\), the number of remaining atoms can be given as:
\[\frac{N_A}{N_B} = \frac{N_0 e^{-\lambda t}}{N_0 e^{-10\lambda t}} = e^{-\lambda t + 10\lambda t} = e^{9\lambda t}\]
This reveals how the comparative rate of decay affects their proportions over time. Such calculations are fundamental in nuclear physics for monitoring isotopic changes and predicting future concentrations in decay chains.
Suppose we take two elements, A and B, with decay constants \(\lambda\) and \(10\lambda\) respectively. After a specific time, \(t\), the number of remaining atoms can be given as:
- For A: \(N_A = N_0 e^{-\lambda t}\)
- For B: \(N_B = N_0 e^{-10\lambda t}\)
\[\frac{N_A}{N_B} = \frac{N_0 e^{-\lambda t}}{N_0 e^{-10\lambda t}} = e^{-\lambda t + 10\lambda t} = e^{9\lambda t}\]
This reveals how the comparative rate of decay affects their proportions over time. Such calculations are fundamental in nuclear physics for monitoring isotopic changes and predicting future concentrations in decay chains.
Other exercises in this chapter
Problem 53
The binding energy of an element is \(64 \mathrm{meV}\). If \(\mathrm{BE} /\) Nucleon is \(6.4\), the number of nucleons are (a) 10 (b) 64 (c) 16 (d) \(6.4\)
View solution Problem 55
Nuclear reactors are usually surrounded by lead and concrete. Which of the following is this safety precaution particularly for? (a) neutron (b) \(\alpha\) part
View solution Problem 58
During a \(\mathrm{K}\)-electron capture (a) X-rays are emitted (b) neutrous are emitted (c) \(\alpha\) particles are emitted (d) \(\gamma\) rays are emitted
View solution Problem 60
\({ }_{7} \mathrm{~N}^{13}\) changes to \({ }_{6} \mathrm{C}^{13}\) by the emission of (a) proton (b) electron (c) neutron (d) positron
View solution