Problem 56
Question
The probability that an archer hits the target is \(p=0.9,\) so the probability that he misses the target is \(q=0.1 .\) It is known that in this situation the probability that the archer hits the target exactly \(r\) times in \(n\) attempts is given by the term containing \(p^{r}\) in the binomial expansion of \((p+q)^{n}\). Find the probability that the archer hits the target exactly three times in five attempts.
Step-by-Step Solution
Verified Answer
The probability is 0.0729.
1Step 1: Understand the Problem
We have an archer with a probability of hitting the target as \( p = 0.9 \) and missing the target as \( q = 0.1 \). We are asked to find the probability that the archer hits the target exactly "3 times" out of "5 attempts".
2Step 2: Use the Binomial Probability Formula
The probability of hitting the target exactly \( r \) times in \( n \) attempts follows a binomial distribution. The binomial probability is given by: \[ P(X = r) = \binom{n}{r} p^r q^{n-r} \]For our problem: - \( n = 5 \) (number of attempts)- \( r = 3 \) (exact number of hits)- \( p = 0.9 \) (probability of hitting the target)- \( q = 0.1 \) (probability of missing the target)
3Step 3: Calculate the Binomial Coefficient
Compute the binomial coefficient \( \binom{5}{3} \), which represents "5 choose 3" or the number of ways to choose 3 hits out of 5 attempts:\[ \binom{5}{3} = \frac{5!}{3!(5-3)!} = \frac{5 \times 4}{2 \times 1} = 10 \]
4Step 4: Compute the Powers of Success and Failure
Calculate the power of success, \( p^3 \):\[ p^3 = (0.9)^3 = 0.729 \]Calculate the power of failure, \( q^{5-3} = q^2 \):\[ q^2 = (0.1)^2 = 0.01 \]
5Step 5: Calculate the Probability
Substitute the values into the binomial formula to find the probability of exactly 3 hits:\[ P(X = 3) = \binom{5}{3} p^3 q^2 = 10 \times 0.729 \times 0.01 = 0.0729 \]
6Step 6: State the Final Probability
Thus, the probability that the archer hits the target exactly three times in five attempts is 0.0729.
Key Concepts
Understanding Probability TheoryExploring the Binomial CoefficientAPPLICATION OF THE BINOMIAL PROBABILITY FORMULA
Understanding Probability Theory
Probability theory is a branch of mathematics that deals with calculating how likely an event is to occur. It's a foundational concept for statistics and important for making predictions about future events. In this context, we focus on discrete probability, which deals with events that occur in countable sample spaces. An example is the probability of an archer hitting a target, as in our task.
Key aspects of probability theory include:
Key aspects of probability theory include:
- Events: Outcomes or sets of outcomes from a random experiment. For the archer, each shot is an event.
- Probability: A numerical value between 0 and 1 that quantifies how likely an event is to happen. A probability of 0 means impossibility, while 1 means certainty.
- Complementary Events: If hitting the target is an event, missing it is the complementary event.
Exploring the Binomial Coefficient
The binomial coefficient is a crucial part of solving problems involving binomial distributions. It is represented as \( \binom{n}{r} \) and is read as "n choose r". Its primary function is to calculate the number of ways to choose \( r \) successes (or hits, in our case) out of \( n \) total trials. Here's how it works:
- The formula is \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where "!" denotes a factorial.
- The formula is \( \binom{n}{r} = \frac{n!}{r!(n-r)!} \), where "!" denotes a factorial.
- Factorial (\( n! \)): Means multiplying all whole numbers from 1 up to \( n \).
- This means choosing 3 successful hits from 5 total shots.
- Using the formula: \( \frac{5!}{3! \times 2!} = 10 \).
- This tells us there are 10 ways the archer can hit the target exactly 3 times.
APPLICATION OF THE BINOMIAL PROBABILITY FORMULA
The binomial probability formula allows us to calculate the probability of achieving exactly \( r \) successes in \( n \) independent trials, with each trial having the same probability of success \( p \). The formula is given by: \[ P(X = r) = \binom{n}{r} p^r (1-p)^{n-r} \] Here, each component plays a role:
- \( \binom{n}{r} \): Indicates the possible ways to achieve \( r \) successes.- \( p^r \): Represents the probability of \( r \) successes happening.- \( (1-p)^{n-r} \): Stands for the probability of the other \( n-r \) trials resulting in failure.For the archer hitting the target 3 times in 5 attempts with \( p = 0.9 \):
- \( \binom{n}{r} \): Indicates the possible ways to achieve \( r \) successes.- \( p^r \): Represents the probability of \( r \) successes happening.- \( (1-p)^{n-r} \): Stands for the probability of the other \( n-r \) trials resulting in failure.For the archer hitting the target 3 times in 5 attempts with \( p = 0.9 \):
- Calculate \( \binom{5}{3} = 10 \)
- Power of success: \( 0.9^3 = 0.729 \)
- Power of failure: \( 0.1^2 = 0.01 \)
Other exercises in this chapter
Problem 55
Show that a right triangle whose sides are in arithmetic progression is similar to a \(3-4-5\) triangle.
View solution Problem 55
Write the sum without using sigma notation. $$\sum_{k=1}^{5} \sqrt{k}$$
View solution Problem 56
Determine whether the infinite geometric series is convergent or divergent. If it is convergent, find its sum. $$\frac{1}{3^{6}}+\frac{1}{3^{8}}+\frac{1}{3^{10}
View solution Problem 56
Find the product of the numbers $$ 10^{1 / 100}, 10^{2 / 10}, 10^{3 / 10}, 10^{4 / 10}, \ldots, 10^{19 / 10} $$
View solution