Problem 56
Question
The basic "dimensions" of mechanics are length, mass, and time. Trigonometric functions are unitless because they represent the ratio of two lengths-the units cancel. Arguments of trigonometric functions are angles and so unitless. Likewise, exponential functions are unitless and take unitless arguments. Suppose that \(t\) represents time, \(y\) distance. If we change the units of either \(t\) or \(y=f(t)\) or both, then we change the numerical value of \(d y / d t .\) For example, 60 miles per hour is the same speed as 88 feet per second. Explain how the Chain Rule accounts for the numerical change in \(d y / d t\) when we change the units of \(y\) and \(t\).
Step-by-Step Solution
Verified Answer
The Chain Rule adjusts \( \frac{dy}{dt} \) by scaling for unit changes in \( t \) and \( y \).
1Step 1: Understanding the Chain Rule
The Chain Rule in calculus is a formula to compute the derivative of a composite function. If we have two functions, say \( g(t) \) and \( y = f(g(t)) \), then the derivative \( \frac{dy}{dt} \) is given by \( \frac{dy}{dg} \cdot \frac{dg}{dt} \). This principle can also be applied to understand the effect of unit changes in problems involving rates.
2Step 2: Changing Units for Time and Distance
When units for time \( t \) change, such as from hours to seconds, the value of \( \frac{dt}{dT} \) changes. Similarly, if the unit of the distance \( y \) changes, such as from miles to feet, then \( \frac{dy}{dY} \) changes. These derivatives represent the scaling factors between old and new units.
3Step 3: Applying the Chain Rule with Unit Changes
Assume \( y = f(T) \) where \( T \) and \( Y \) are the new units for time and distance. To find \( \frac{dy}{dt} \), use the Chain Rule: \( \frac{dy}{dt} = \frac{dy}{dY} \cdot \frac{dY}{dT} \cdot \frac{dT}{dt} \). Here, \( \frac{dy}{dY} \) and \( \frac{dT}{dt} \) are scaling factors converting old units to new ones.
4Step 4: Example Calculation of Speed Conversion
Consider converting speed from miles per hour to feet per second. The conversion factor for distance is \( \frac{5280 \text{ feet}}{1 \text{ mile}} \), and the conversion for time is \( \frac{1 \text{ hour}}{3600 \text{ seconds}} \). Thus, \( 60 \text{ miles/hour} = 60 \times 5280 / 3600 \text{ ft/sec} \). The Chain Rule helps adjust by these conversion factors, modifying numerical values based on unit change.
Key Concepts
Unit ConversionDerivativesRate of ChangeTrigonometric Functions
Unit Conversion
Unit conversion is a crucial aspect of understanding different rates and their calculations. When you convert units, you're changing the method of measurement without altering the actual quantity. This might seem straightforward, but it can lead to different numerical results, especially in the context of derivatives where rates of change are involved.
To convert units:
To convert units:
- Identify the original units and desired new units.
- Find the conversion factor between these units. For example, 1 mile is equivalent to 5280 feet, and 1 hour is equivalent to 3600 seconds.
- Multiply the original measurement by this conversion factor to get the equivalent value in the new units.
Derivatives
Derivatives are a fundamental concept in calculus, representing the rate at which a function is changing at any given point. Practically, this can help us understand various real-world changes, like speed or growth rates.
For a function like distance over time, the derivative \(\frac{dy}{dt}\), represents instantaneous speed. This derivative tells us how fast the distance \(y\) is changing with respect to time \(t\). Importantly, when units for \(y\) or \(t\) are changed, the numerical value of \(\frac{dy}{dt}\) changes due to the new scales of measurement involved.
By understanding derivatives and their role in describing change, one can apply mathematical operations to even complex scenarios like converting different units while still tracking how one variable influences another.
For a function like distance over time, the derivative \(\frac{dy}{dt}\), represents instantaneous speed. This derivative tells us how fast the distance \(y\) is changing with respect to time \(t\). Importantly, when units for \(y\) or \(t\) are changed, the numerical value of \(\frac{dy}{dt}\) changes due to the new scales of measurement involved.
By understanding derivatives and their role in describing change, one can apply mathematical operations to even complex scenarios like converting different units while still tracking how one variable influences another.
Rate of Change
The rate of change is a measure of how a quantity alters with respect to another quantity. It's essentially what a derivative captures in a calculus sense. Whether it's climbing a hill or considering economic growth, this concept is ubiquitous.
In the context of unit conversion, the rate of change can differ simply because the units change. For instance, converting speed from miles per hour to feet per second involves recalculating the rate of distance change over time. This is where applying the chain rule becomes vital, as it allows us to consider the actual change of units and how it impacts the rate.
Understanding the rate of change is key in many fields, from physics to finance, aiding in optimizations and predictions.
In the context of unit conversion, the rate of change can differ simply because the units change. For instance, converting speed from miles per hour to feet per second involves recalculating the rate of distance change over time. This is where applying the chain rule becomes vital, as it allows us to consider the actual change of units and how it impacts the rate.
Understanding the rate of change is key in many fields, from physics to finance, aiding in optimizations and predictions.
Trigonometric Functions
Trigonometric functions might feel unrelated to unit conversion at first, but they provide a good example of functions that are inherently unitless. Functions like sine, cosine, and tangent relate ratios of sides in a triangle.
The arguments of trigonometric functions, usually angles measured in degrees or radians, do not include units. This is because these functions represent ratios — a concept that transcends particular units. This unitless nature makes them unique compared to other mathematical functions.
When considering derivatives, understanding trigonometric functions' properties helps maintain their ratios correctly, without needing unit conversions for the arguments themselves. While the angles may be converted between degrees and radians, the inherently relative nature of trigonometric functions remains.
The arguments of trigonometric functions, usually angles measured in degrees or radians, do not include units. This is because these functions represent ratios — a concept that transcends particular units. This unitless nature makes them unique compared to other mathematical functions.
When considering derivatives, understanding trigonometric functions' properties helps maintain their ratios correctly, without needing unit conversions for the arguments themselves. While the angles may be converted between degrees and radians, the inherently relative nature of trigonometric functions remains.
Other exercises in this chapter
Problem 56
A function \(f,\) a point \(c,\) an increment \(\Delta x,\) and a positive integer \(n\) are given. Use the method of increments to estimate \(f(c+\Delta x)\).
View solution Problem 56
Suppose that \(A \neq 0 .\) The locus of $$ x^{2 / 3}+y^{2 / 3}=a^{2 / 3} $$ is called an astroid \(\mathcal{A}_{a} .\) Let \(T\) be a tangent line to the astro
View solution Problem 56
Suppose that \(f\) and \(g\) are twice differentiable. Calculate a formula for \((f / g)^{\prime \prime}\).
View solution Problem 56
In Exercises \(56-59\), evaluate the derivative \(f^{\prime}\) of the given function \(f\) in two ways. First, apply the Chain Rule to \(f(x)\) without simplify
View solution