Problem 56
Question
Suppose a rocket is launched from the surface of the earth. If we disregard the effect of the sun, the work required to propel the rocket from the surface ( 3960 miles from the center of the earth) to \(x\) miles above the surface is given by the formula $$ W(x)=G M m\left(\frac{1}{3960}-\frac{1}{x}\right) $$ where \(G, M\), and \(m\) are constants. Find the work required to send the rocket from here to the end of the universe. Leave your answer in terms of \(G, M\), and \(m\).
Step-by-Step Solution
Verified Answer
The work required is \( \frac{G M m}{3960} \).
1Step 1: Understanding the Formula
The given formula for work is \( W(x) = G M m \left( \frac{1}{3960} - \frac{1}{x} \right) \). Here, \( G, M, \) and \( m \) are constants that represent gravitational constant, mass of the Earth, and mass of the rocket, respectively. The objective is to determine the work \( W \) required to send the rocket to an infinite distance, i.e., to the end of the universe.
2Step 2: Analyzing Work to Infinity
Sending the rocket to the end of the universe implies taking the limit as \( x \) approaches infinity. Thus, we need to evaluate \( W(\infty) = G M m \left( \frac{1}{3960} - \frac{1}{\infty} \right) \). Since \( \frac{1}{\infty} = 0 \), the expression simplifies considerably.
3Step 3: Simplifying the Expression
Substituting \( \frac{1}{\infty} = 0 \) into the expression, we have:\[W(\infty) = G M m \left( \frac{1}{3960} - 0 \right) = G M m \times \frac{1}{3960}.\]Thus, the work required is simplified to \( \frac{G M m}{3960} \).
Key Concepts
Gravitational ConstantWork-Energy PrincipleLimits in Calculus
Gravitational Constant
The gravitational constant, denoted by \( G \), is a crucial value in the physics realm, underpinning the laws of gravitation as we know them today. This constant acts as a scaling factor in Newton's law of universal gravitation:
- It is used to calculate the gravitational attraction between two masses.
- The value of \( G \) is approximately \( 6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \).
- It is a measure of how strongly bodies of mass influence one another through gravitational force.
Work-Energy Principle
The work-energy principle is a key concept that helps us understand the relationship between force applied, work done, and energy changes associated with motion. This principle states that the work done by all forces acting on an object equals the change in its kinetic energy.
- Work is done when energy is transferred from one system to another, usually through force causing movement.
- In our context, work \( W(x) \) represents the energy needed to move a rocket against Earth's gravitational pull.
- By calculating this work, we can determine how much energy is required to reach varying heights, eventually extending to theoretically infinite distances.
Limits in Calculus
Limits in calculus are powerful tools allowing us to analyze behavior as variables approach certain values, including infinity. In this exercise, we used limits to explore the conditions necessary for the rocket making its journey to infinity.
- Introducing limits allows us to deal with changes in distance represented by \( x \) as it extends towards infinity.
- Calculating \( \lim_{x \to \infty} \left( \frac{1}{x} \right) = 0 \) showcases how the infinitesimal values diminish to zero.
- Using limits, we simplify complex ideas, such as determining how much work \( W(\infty) \) is truly needed to overcome gravitational forces to send the rocket infinitely far.
Other exercises in this chapter
Problem 55
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