Problem 56
Question
Sketch each scaling relation (Niklas, 1994). Suppose that a cube of length \(L\) and volume \(V\) has mass \(M\) and that \(M=0.35 V\). How does the length of the cube depend on its mass?
Step-by-Step Solution
Verified Answer
The cube's length \(L\) depends on its mass \(M\) as \(L = \left(\frac{M}{0.35}\right)^{1/3}\).
1Step 1: Define the Volume Formula
A cube with length \(L\) has a volume \(V\), which can be expressed in terms of its side length \(L\) as \(V = L^3\).
2Step 2: Substitute for Volume in Mass Equation
We know that the mass \(M\) is given by the equation \(M = 0.35V\). Substitute \(V = L^3\) into this equation, obtaining \(M = 0.35L^3\).
3Step 3: Solve for Length \(L\) in Terms of Mass \(M\)
To express \(L\) in terms of \(M\), solve the equation \(M = 0.35L^3\) for \(L\). First, divide both sides by 0.35 to get \(L^3 = \frac{M}{0.35}\). Then take the cube root to solve for \(L\), yielding \(L = \left(\frac{M}{0.35}\right)^{1/3}\).
Key Concepts
Volume of a CubeMass-Volume RelationshipCube Root Calculation
Volume of a Cube
When you think of a cube, it's important to visualize it as a three-dimensional shape with equal sides. Each side of this cube is denoted by the length \(L\). So, when calculating its volume, which is essentially the space inside the cube, we use the formula:
- \(V = L^3\)
Mass-Volume Relationship
The connection between a cube's volume and its mass is fascinating and important for scaling relations. In the given problem, this relationship is expressed as:
- \(M = 0.35V\)
Cube Root Calculation
Finding the cube root is an essential mathematical skill, especially when dealing with volumes and side lengths of cubes. Suppose you need to determine the length \(L\) from a given mass \(M\). To do so, you'll use the equation derived from the mass-volume relationship:
- First, solve for \(L^3\) in \(M = 0.35L^3\) by rearranging it to \(L^3 = \frac{M}{0.35}\).
- Then, find the cube root: \(L = \left(\frac{M}{0.35}\right)^{1/3}\).
Other exercises in this chapter
Problem 55
Find the equation of a circle with center \((-1,4)\) and radius \(3 .\)
View solution Problem 56
When \(\log y\) is graphed as a function of \(\log x, a\) straight line results. Graph straight lines, each given by two points, 5n a log-log plot, and determin
View solution Problem 56
Find the equation of a circle with center \((2,3)\) and radius 4 .
View solution Problem 57
When \(\log y\) is graphed as a function of \(\log x, a\) straight line results. Graph straight lines, each given by two points, 5n a log-log plot, and determin
View solution