Problem 56
Question
Sketch a graph of the rectangular equation. [ Hint: First convert the equation to polar coordinates.] $$x^{2}+y^{2}=\left(x^{2}+y^{2}-x\right)^{2}$$
Step-by-Step Solution
Verified Answer
Graph is two lines through the origin at 45° and 135°.
1Step 1: Identify Original Equation
The given equation is \( x^2 + y^2 = (x^2 + y^2 - x)^2 \). We will start by identifying how to convert this into polar coordinates.
2Step 2: Convert to Polar Coordinates
Remember the relationships between rectangular and polar coordinates: \( x = r\cos(\theta) \) and \( y = r\sin(\theta) \). Also, \( x^2 + y^2 = r^2 \). Substitute these into the equation.
3Step 3: Substitute and Simplify
Substituting, the equation becomes \( r^2 = (r^2 - r\cos(\theta))^2 \). Expand the right side to get \( r^2 = r^4 - 2r^3\cos(\theta) + r^2\cos^2(\theta) \).
4Step 4: Simplify Further
Rearrange the terms to have \( r^4 - 2r^3\cos(\theta) + r^2\cos^2(\theta) - r^2 = 0 \). Factor out \( r^2 \) to get \( r^2(r^2 - 2r\cos(\theta) + \cos^2(\theta) - 1) = 0 \).
5Step 5: Consider Factor Solutions
The first factor \( r^2 = 0 \) implies \( r = 0 \), which corresponds to the origin. For the second factor, simplify: \( r^2 - 2r\cos(\theta) + \cos^2(\theta) - 1 = 0 \).
6Step 6: Complete the Square and Solve for r
To solve \( r^2 - 2r\cos(\theta) + \cos^2(\theta) - 1 = 0 \), rearrange as \( (r - \cos(\theta))^2 = 1 - \cos^2(\theta) \), which gives \( (r - \cos(\theta))^2 = \sin^2(\theta) \).
7Step 7: Result and Graphing
Taking the square root, \( r - \cos(\theta) = \pm \sin(\theta) \) gives two solutions: \( r = \cos(\theta) + \sin(\theta) \) and \( r = \cos(\theta) - \sin(\theta) \). Graphing these in polar coordinates results in two intersecting lines through the origin at angles corresponding to \( 45^\circ \) and \( 135^\circ \), intersecting at the origin.
Key Concepts
Graph SketchingRectangular to Polar ConversionTrigonometric IdentitiesCompleting the Square
Graph Sketching
Graph sketching involves drawing a visual representation of equations on a coordinate plane. This exercise transitions from rectangular (or Cartesian) coordinates to polar coordinates. When graphing, it's useful to note the intercepts, symmetry, and shape. In this example, we transform the given equation to a polar form to simplify the graphing process.
In this problem, the solution explores the nature of the equation, revealing lines intersecting at the origin, providing a simpler view for sketching.
- Identify key points such as where the graph crosses the axes.
- Look for symmetry about the origin or the line of interest.
- Consider how the graph behaves as variables tend to infinity or zero.
In this problem, the solution explores the nature of the equation, revealing lines intersecting at the origin, providing a simpler view for sketching.
Rectangular to Polar Conversion
Converting from rectangular to polar coordinates can simplify complex equations. In polar coordinates, each point in the plane is determined by a radius and an angle. The relationships between the two coordinate systems are crucial:
- The x-coordinate translates to polar coordinates via: \( x = r\cos(\theta) \)
- The y-coordinate translates via: \( y = r\sin(\theta) \)
- The equation for a circle or distance from origin is: \( x^2 + y^2 = r^2 \)
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that are true for all angle values. They are vital when working with polar equations as they allow for simplification and manipulation of expressions. In this solution, we use identities to help rearrange and simplify our polar equation. Key identities used include:
- Pythagorean Identity: \( \sin^2(\theta) + \cos^2(\theta) = 1 \)
- Double Angle Formulas and others can help transform and solve equations
Completing the Square
Completing the square is a technique used to transform a quadratic expression into a perfect square binomial, which can then be easily solved or simplified. This technique is helpful in both algebra and coordinate transformations. In the polar equation derived from the original, you've seen the expression \( r^2 - 2r\cos(\theta) + \cos^2(\theta) - 1 = 0 \).
- By rearranging and completing the square as \( (r - \cos(\theta))^2 = 1 - \cos^2(\theta) \), efficient solutions can be found.
- This helps break down the equation into simple binomials that are easier to manipulate and solve.
Other exercises in this chapter
Problem 55
Convert the polar equation to rectangular coordinates. $$r=4 \sin \theta$$
View solution Problem 56
Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\). Express your answer in polar form. $$z_{1}=7\left(\cos \frac{9 \pi}{8}+i \sin \frac{9 \pi}{
View solution Problem 56
Convert the polar equation to rectangular coordinates. $$r=6 \cos \theta$$
View solution Problem 57
Find the product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\). Express your answer in polar form. $$z_{1}=4\left(\cos 120^{\circ}+i \sin 120^{\circ}\right
View solution