Problem 56
Question
Prove each, where \(x \in \mathbb{R}\) and \(n \in \mathbf{Z}\) $$\left[\frac{n^{2}}{4}\right]=\frac{n^{2}+3}{4} \text { if } n \text { is odd }$$
Step-by-Step Solution
Verified Answer
Given that \(n\) is odd, we can express it as \(n=2k+1\). The left-hand side of the equation \(\left[\frac{n^{2}}{4}\right] = \left[\frac{(2k+1)^{2}}{4}\right] = \left[\frac{4k^2 + 4k + 1}{4}\right] = k^2+k\). The right-hand side of the equation \(\frac{n^{2}+3}{4} = \frac{(2k+1)^{2}+3}{4} = \frac{4k^2 + 4k + 1 + 3}{4} = k^2+k\). Since both sides are equal, the statement is proven: \(\left[\frac{n^{2}}{4}\right] = \frac{n^{2}+3}{4}\) if \(n\) is odd.
1Step 1: Identify Important Definitions
Before diving into the proof, let's first understand some terms and definitions that will be important for our proof.
1. Odd integers: An integer n is odd if there exists another integer k such that n = 2k + 1.
2. The floor function: \(\left[\frac{n^{2}}{4}\right]\) denotes the largest integer less than or equal to \(\frac{n^{2}}{4}\).
2Step 2: Express Odd Integer as 2k+1
We are given that n is an odd integer, so we can express it as \(n = 2k + 1\) where k is any integer.
3Step 3: Work with the Left-hand Side of the Equation
Let's handle the left-hand side of the equation first. We have:
\(\left[\frac{n^{2}}{4}\right] = \left[\frac{(2k+1)^{2}}{4}\right]\)
Next, we will expand the numerator:
\(\left[\frac{(2k+1)^{2}}{4}\right] = \left[\frac{4k^2 + 4k + 1}{4}\right]\)
4Step 4: Simplify the Left-hand Side of the Equation
We can now factor out the common factor of 4 from the numerator and simplify the expression:
\(\left[\frac{4k^2 + 4k + 1}{4}\right] = \left[\frac{4(k^2 + k) + 1}{4}\right]\)
As we have a term with only integer numbers and one term that is a fraction, then:
\(\left[\frac{4(k^2 + k) + 1}{4}\right] = \left[\frac{4(k^2 + k)}{4}\right] + \left[\frac{1}{4}\right] = k^2+k\)
5Step 5: Work with the Right-hand Side of the Equation
Now let's handle the right-hand side of the equation. We have:
\(\frac{n^{2}+3}{4} = \frac{(2k+1)^{2}+3}{4}\)
Next, we will expand the numerator:
\(\frac{(2k+1)^{2}+3}{4} = \frac{4k^2 + 4k + 1 + 3}{4}\)
6Step 6: Simplify the Right-hand Side of the Equation
We can now factor out the common factor of 4 from the numerator and simplify the expression:
\(\frac{4k^2 + 4k + 1 + 3}{4} = \frac{4(k^2 + k) + 4}{4} = k^2+k\)
7Step 7: Conclude the Proof
Since we have shown that both left-hand side and right-hand side expressions are equal to \(k^2 + k\), we conclude the proof:
\(\left[\frac{n^{2}}{4}\right] = \frac{n^{2}+3}{4}\) if n is odd.
Key Concepts
Odd IntegersFloor FunctionProof Techniques
Odd Integers
In discrete mathematics, odd integers are a fundamental concept. An odd integer is any integer that cannot be evenly divided by 2. This means if you take any integer \( n \), it is called odd if there exists an integer \( k \) such that \( n = 2k + 1 \).
This formula arises because when you multiply any integer \( k \) by 2, you get an even number. By adding 1, you move to the next odd integer.
Examples of odd integers include:
This formula arises because when you multiply any integer \( k \) by 2, you get an even number. By adding 1, you move to the next odd integer.
Examples of odd integers include:
- 1 (which can be expressed as \( 2 \times 0 + 1 \))
- 3 (which can be expressed as \( 2 \times 1 + 1 \))
- 5 (which can be expressed as \( 2 \times 2 + 1 \))
Floor Function
The floor function is an essential mathematical concept. It is often represented using square brackets: \( \left[ x \right] \). The floor function of a real number \( x \), \( \left[ x \right] \), is defined as the greatest integer less than or equal to \( x \).
In simpler terms, the floor function rounds a number down to the nearest whole number less than or equal to the original number. For example:
In simpler terms, the floor function rounds a number down to the nearest whole number less than or equal to the original number. For example:
- \( \left[ 3.7 \right] = 3 \) (since 3 is the largest integer \( \leq 3.7 \))
- \( \left[ -2.1 \right] = -3 \) (since -3 is the largest integer \( \leq -2.1 \))
Proof Techniques
Proof techniques are methods employed to establish the truth of mathematical statements. In the exercise above, we use algebraic manipulation to prove an equation.
The proof starts by acknowledging definitions and properties of the involved mathematical elements such as odd integers and floor functions. Then, a strategy is employed:
The proof starts by acknowledging definitions and properties of the involved mathematical elements such as odd integers and floor functions. Then, a strategy is employed:
- Substitution: Replacing odd integers with their expression \( n = 2k + 1 \).
- Simplification: Expanding and simplifying both sides of the equation.
- Comparative Analysis: Demonstrating that both simplified forms (left-hand side and right-hand side) are identical.
Other exercises in this chapter
Problem 56
Let \(M\) denote the set of \(2 \times 2\) matrices over \(\mathbf{w} .\) Let \(f : N \rightarrow M\) defined by \(f(n)=\left[\begin{array}{ll}{1} & {1} \\ {1}
View solution Problem 56
Prove each, where \(X \sim Y\) implies set \(X\) is equivalent to set \(Y\). If \(A \sim B\) and \(B \sim C,\) then \(A \sim C\) (transitive property).
View solution Problem 57
Prove each, where \(x \in \mathbb{R}\) and \(n \in \mathbf{Z}.\) \(\left\lfloor\frac{n}{2}\right\rfloor+\left\lceil\frac{n}{2}\right\rceil= n\)
View solution Problem 57
Prove each. The inverse of a square matrix \(A\) is unique. (Hint: Assume \(A\) has two inverses \(B\) and \(C\) . Show that \(B=C\) . \()\)
View solution