Problem 56
Question
Multiply. Write all answers in the form \(a+b i\) See Example 5 . $$ 2 i(7+2 i) $$
Step-by-Step Solution
Verified Answer
The result is \(-4 + 14i\).
1Step 1: Distribute 2i
To multiply the expression \(2i(7+2i)\), we need to distribute \(2i\) to each term within the parentheses. This gives us two separate multiplications to evaluate: \(2i \cdot 7\) and \(2i \cdot 2i\).
2Step 2: Calculate each multiplication
Let's start with \(2i \cdot 7\). Multiply the real number by the imaginary unit: \(2i \cdot 7 = 14i\).Next, calculate \(2i \cdot 2i\). Remember that \(i^2 = -1\), so: \[2i \cdot 2i = 4i^2 = 4(-1) = -4\].
3Step 3: Combine the results
Now we combine the results from Step 2: \[14i + (-4)\]. This simplifies to \(-4 + 14i\).
4Step 4: Express in form \(a+bi\)
Write the complex number \(-4 + 14i\) in the form \(a+bi\), where \(a=-4\) and \(b=14\).
Key Concepts
Multiplication of Complex NumbersImaginary UnitDistributive Property
Multiplication of Complex Numbers
Complex numbers are numbers that have both a real and an imaginary part. The imaginary part includes the term with the imaginary unit, often symbolized by the letter \(i\). When multiplying complex numbers, it is essential to apply the distributive property, a key algebraic principle.
In multiplication, each part of one complex number multiplies with each part of the other. For the expression \(2i(7+2i)\), we need to follow this method by distributing \(2i\) to both terms inside the parentheses:
In multiplication, each part of one complex number multiplies with each part of the other. For the expression \(2i(7+2i)\), we need to follow this method by distributing \(2i\) to both terms inside the parentheses:
- First, multiply \(2i\) by the real number term \(7\).
- Then, multiply \(2i\) by the imaginary term \(2i\).
Imaginary Unit
The imaginary unit, denoted by \(i\), is a fundamental concept in complex numbers. It is defined by the property \(i^2 = -1\). This definition allows us to solve equations that do not have solutions in the set of real numbers alone. The imaginary unit forms the basis for the imaginary part of complex numbers.
During multiplication involving the imaginary unit, it is crucial to apply the property of \(i\) correctly. In our example, the multiplication \(2i \cdot 2i\) demonstrates how the use of \(i^2 = -1\) turns what initially seems to be a complex result into a real number:
During multiplication involving the imaginary unit, it is crucial to apply the property of \(i\) correctly. In our example, the multiplication \(2i \cdot 2i\) demonstrates how the use of \(i^2 = -1\) turns what initially seems to be a complex result into a real number:
- Calculate \(2i \cdot 2i\) as \(4i^2\).
- Recognize that \(i^2\) equates to \(-1\), which transforms the multiplication into \(4(-1) = -4\).
Distributive Property
The distributive property is a fundamental concept used to simplify expressions and solve equations. It states that \(a(b+c) = ab + ac\). This property allows us to distribute one quantity over a sum or difference within parentheses, providing a clear path to simplifying complex expressions.
When multiplying complex numbers, this property is particularly useful. It allows us to multiply each part of the complex number separately by the number outside the parentheses. In the example \(2i(7+2i)\), applying the distributive property:
When multiplying complex numbers, this property is particularly useful. It allows us to multiply each part of the complex number separately by the number outside the parentheses. In the example \(2i(7+2i)\), applying the distributive property:
- We first distribute \(2i\) to \(7\) (\(2i \cdot 7 = 14i\)).
- Next, distribute \(2i\) to \(2i\) (\(2i \cdot 2i = 4i^2 = -4\)).
Other exercises in this chapter
Problem 56
Rationalize each denominator. $$ \sqrt{\frac{5}{3}} $$
View solution Problem 56
Find the midpoint of the line segment with the given endpoints. \((10,12),(0,0)\)
View solution Problem 56
Simplify by combining like radicals. $$ 4+\sqrt{8}+\sqrt{2}+8 $$
View solution Problem 56
Solve each equation. Write all proposed solutions. Cross out those that are extraneous. $$ \sqrt{x-7}+\sqrt{x}=7 $$
View solution