Problem 56
Question
Multiply the algebraic expressions using a Special Product Formula, and simplify. \((r-2 s)^{2}\)
Step-by-Step Solution
Verified Answer
The simplified expression is \(r^2 - 4rs + 4s^2\).
1Step 1: Identify the Formula
The expression \((r - 2s)^2\) is a square of a binomial. This fits the special product formula \((a - b)^2 = a^2 - 2ab + b^2\). Here, \(a = r\) and \(b = 2s\).
2Step 2: Apply the Formula
Substitute \(a\) and \(b\) into the formula: \((r - 2s)^2 = r^2 - 2(r)(2s) + (2s)^2\).
3Step 3: Calculate Each Term
Compute each part of the formula: - \(r^2\) is simply \(r^2\).- \(-2(r)(2s) = -4rs\).- \((2s)^2 = 4s^2\).
4Step 4: Write the Expression
Combine the calculated terms: The expression simplifies to \(r^2 - 4rs + 4s^2\).
Key Concepts
Binomial SquareAlgebraic ExpressionsSimplifying Expressions
Binomial Square
When you encounter a binomial, you are dealing with an expression that contains two terms. In this case, our binomial is \((r-2s)\). Squaring a binomial means multiplying the binomial by itself. The expression becomes \((r-2s) \times (r-2s)\). However, there's a quicker way to solve this using the binomial square formula:
- For a binomial squared, the formula is \((a-b)^2 = a^2 - 2ab + b^2\), where each term of the binomial is squared, and twice their product is also included.
- In our exercise with \((r-2s)^2\), you identify \(a=r\) and \(b=2s\).
- Applying the formula can significantly simplify your work and avoid potential calculation errors in basic algebra.
Algebraic Expressions
Algebraic expressions, like \((r-2s)^2\), allow us to describe relationships between different quantities using variables and numbers.
These expressions can include operators such as addition, subtraction, multiplication, and division, and they frequently incorporate parentheses to dictate the order of operations.
Each component in an algebraic expression plays a unique role:
These expressions can include operators such as addition, subtraction, multiplication, and division, and they frequently incorporate parentheses to dictate the order of operations.
Each component in an algebraic expression plays a unique role:
- Variables represent unknown quantities and are typically denoted by letters like \(r\) and \(s\).
- Coefficients, like the \(2\) in \(2s\), multiply the variables and represent known quantities.
- Constants are fixed values that appear without variables, but there are none in this particular expression.
Simplifying Expressions
Simplifying expressions involves reducing them to a simpler form or a particular type of finished form.
Simplifying \((r-2s)^2\) requires following a sequence of operations by applying the special product formula.
Key steps include:
Simplifying \((r-2s)^2\) requires following a sequence of operations by applying the special product formula.
Key steps include:
- Apply the formula: Start by using \((a - b)^2 = a^2 - 2ab + b^2\) which gives you a roadmap for what the simplified expression should look like.
- Compute each term: First, find \(a^2\), which is \(r^2\). Then \(-2ab\ = -4rs\), and finally \(b^2 = 4s^2\).
- Combine terms: Once computed, put \(r^2\), \(-4rs\), and \(4s^2\) together to simplify the expression to \(r^2 - 4rs + 4s^2\).
Other exercises in this chapter
Problem 56
Evaluate each expression. $$ \begin{array}{ll}{\text { (a) }|2-|-12| |} & {\text { (b) }-1-|1-|-1| |}\end{array} $$
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\(49-68=\) Simplify the expression and eliminate any negative exponent(s). Assume that all letters denote positive numbers. $$ \left(4 a^{6} b^{8}\right)^{3 / 2
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Perform the addition or subtraction and simplify. $$ \frac{2}{x+3}-\frac{1}{x^{2}+7 x+12} $$
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\(47-72\) . Simplify the expression, and eliminate any negative exponent(s). $$ \frac{6 y^{3} z}{2 y z^{2}} $$
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