Problem 56
Question
Let \(a_{n}\) be the \(n^{\text {th }}\) term of a G.P. of positive terms. If \(\sum_{n=1}^{100} a_{2 n+1}=200\) and \(\sum_{n=1}^{100} a_{2 n}=100\), then \(\sum_{n=1}^{200} a_{n}\) is equal to: [Jan. 9, 2020 (II)] (a) 300 (b) 225 (c) 175 (d) 150
Step-by-Step Solution
Verified Answer
The sum \(\sum_{n=1}^{200} a_{n}\) equals 300. Answer: (a) 300.
1Step 1: Understand Given Terms
We are given two separate series sums involving the terms of a geometric progression (G.P.). The summation \(\sum_{n=1}^{100} a_{2n+1}=200\) represents the sum of 100 terms where each term is of the form \(a_{2n+1}\). On the other hand, the summation \(\sum_{n=1}^{100} a_{2n}=100\) represents the sum of 100 terms where each term is of the form \(a_{2n}\).
2Step 2: Express Summations in G.P. Form
For a geometric progression, the general term can be represented using the first term \(a\) and the common ratio \(r\) as \(a_n = a \cdot r^{n-1}\). Therefore, \(a_{2n+1} = a \cdot r^{2n}\) and \(a_{2n} = a \cdot r^{2n-1}\).
3Step 3: Calculate Individual Sums
The sum \(\sum_{n=1}^{100} a_{2n+1}=200\) can be expressed as a geometric series: \[ a \cdot r^2 + a \cdot r^4 + \ldots + a \cdot r^{200} = 200 \]Similarly, the sum \(\sum_{n=1}^{100} a_{2n}=100\) can be expressed as: \[ (a \cdot r) + (a \cdot r^3) + \ldots + (a \cdot r^{199}) = 100 \]
4Step 4: Relationship Between Series
Notice that each term of the second sum is \(r\) times each term of the first sum, i.e., the terms in \(S_2\) are the terms in \(S_1\) multiplied by \(r\). Thus, the sums relate by the equation: \[ S_2 = r \cdot S_1 \]Substituting known values: \[ 100 = r \cdot 200 \]This gives \(r=0.5\).
5Step 5: Find Total Sum
Now, we need to calculate \(\sum_{n=1}^{200} a_{n}\), which is the sum of all terms in the progression. We utilize the first sum (\(S_1\)) and second sum (\(S_2\)): \[ S = S_1 + S_2 = 200 + 100 = 300 \]
6Step 6: Conclusion
The total sum \(\sum_{n=1}^{200} a_{n}\) is calculated by adding the results from the summations of odd and even indexed terms.
Key Concepts
Sequences and SeriesGeometric Progression (G.P.)Summation of SeriesCommon Ratio
Sequences and Series
In mathematics, a sequence refers to a set of numbers arranged in a specific order following a particular rule. A series is the sum of the terms of a sequence. Sequences are foundational in understanding mathematics and play a crucial role in higher-level studies, such as in calculus and discrete mathematics. Common sequences include arithmetic and geometric sequences. The sum of an infinite sequence can also converge to a particular value, depending on the properties of the sequence. Understanding sequences and their related series help in solving complex mathematical problems by breaking them down into simpler, more manageable parts.
- Arithmetic Sequences: Have a constant difference between terms.
- Geometric Sequences: Each term is a constant multiple of the previous term.
Geometric Progression (G.P.)
A geometric progression (G.P.) is a sequence of numbers where each term after the first is obtained by multiplying the previous one by a fixed, non-zero number called the common ratio. Geometric progressions are widely used in various branches of mathematics as they can model exponential growth or decay, relevant in fields like finance, sciences, and engineering. In the general form of a G.P., each term can be expressed as:
- General Term: If the first term is denoted by \( a \) and the common ratio by \( r \), then the \( n^{th} \) term is given by \( a_n = a \, r^{n-1} \).
Summation of Series
Summing a series refers to finding the total when all terms in the sequence are added together. For a geometric series, this involves adding all the terms from a geometric progression. The formula to find the sum of the first \( n \) terms of a G.P. is:
- For \( n \) terms: \( S_n = a \frac{1 - r^n}{1 - r} \), where \( a \) is the first term and \( r \) is the common ratio ( \( r eq 1 \)).
Common Ratio
The common ratio in a geometric progression is the factor by which we multiply a term to get the next term. It is a vital component of the sequence as it dictates the progression's behavior, whether it grows or shrinks. To determine the common ratio, divide any term by its preceding term:
- Formula: \( r = \frac{a_{n+1}}{a_n} \)
Other exercises in this chapter
Problem 53
If \(|x|
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Let \(a_{1}, a_{2}, a_{3}, \ldots\) be \(a \mathrm{G} .\) P. such that \(a_{1}
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