Problem 56
Question
In Exercises \(53-56,\) find the point in which the line meets the plane. $$ x=-1+3 t, \quad y=-2, \quad z=5 t ; \quad 2 x-3 z=7 $$
Step-by-Step Solution
Verified Answer
The intersection point is (-4, -2, -5).
1Step 1: Understand the Problem
We need to find the point of intersection between a line and a plane. The line is given by the parametric equations \( x = -1 + 3t \), \( y = -2 \), and \( z = 5t \). The plane has the equation \( 2x - 3z = 7 \).
2Step 2: Substitute Line Equations into the Plane Equation
Substitute the expressions for \( x \) and \( z \) from the line into the plane's equation. This gives:\[2(-1 + 3t) - 3(5t) = 7.\]
3Step 3: Simplify the Equation
Simplify the equation from Step 2:\[-2 + 6t - 15t = 7.\]Combine like terms to get:\[-9t - 2 = 7.\]
4Step 4: Solve for the Parameter \( t \)
Solve the equation for \( t \):\[-9t = 7 + 2 \-9t = 9 \t = -1.\]
5Step 5: Find the Intersection Point Coordinates
Now that we have \( t = -1 \), substitute this value back into the parametric equations of the line to find the coordinates of the intersection point:\(x = -1 + 3(-1) = -4, \y = -2, \z = 5(-1) = -5.\) Hence, the intersection point is \((-4, -2, -5)\).
6Step 6: Verify the Solution
Substitute the coordinates \((-4, -2, -5)\) into the plane's equation to verify:\[2(-4) - 3(-5) = -8 + 15 = 7.\] The plane's equation is satisfied, confirming that the intersection point is correct.
Key Concepts
Parametric EquationsIntersection PointPlane Equation
Parametric Equations
Parametric equations are a fundamental way to represent a line in three-dimensional space. They define the coordinates of any point on the line in terms of a single variable, often called the parameter, denoted as \(t\). This method of line representation is particularly useful when dealing with problems involving intersections between lines and surfaces like planes. In the given exercise, the line is represented in parametric form as follows:
- \(x = -1 + 3t\)
- \(y = -2\)
- \(z = 5t\)
Intersection Point
The intersection point is where the line meets the plane. To find this point, we need to solve for the parameter \(t\) that satisfies both the line's parametric equations and the plane equation. Once \(t\) is determined, it can be plugged back into the line's equations to find the specific coordinates of the intersection.To find \(t\), we substitute the expressions for \(x\) and \(z\) from the parametric equations into the plane's equation:\[ 2(-1 + 3t) - 3(5t) = 7 \]After simplifying and solving, we find \(t = -1\). With \(t\) known, we substitute back into:
- \(x = -1 + 3(-1) = -4\)
- \(y = -2\)
- \(z = 5(-1) = -5\)
Plane Equation
A plane in three-dimensional space can be described by an equation of the form \(Ax + By + Cz = D\), where \(A\), \(B\), and \(C\) are constants that determine the plane's orientation, and \(D\) is another constant. The given exercise uses the plane equation:\[ 2x - 3z = 7 \]This equation states that there is a continuous set of points \((x, y, z)\) satisfying this condition, forming a flat surface in 3D space. For solving the intersection problem, we focus on the substitutes for coordinates from the line into this equation.The absence of \(y\) in this plane equation indicates that the plane is parallel to the \(y\)-axis in the \(x-z\) plane. As a result, the value of \(y\) from the parametric equation directly carries over to the intersection point.Understanding the orientation and characteristics of the plane helps in visualizing and solving geometry-based problems. Plane equations are pivotal in fields such as computer-aided design (CAD) and geographic information systems (GIS), where accurate spatial representations are needed.
Other exercises in this chapter
Problem 55
Find the centers and radii of the spheres in Exercises \(55-58 .\) $$x^{2}+y^{2}+z^{2}+4 x-4 z=0$$
View solution Problem 55
Suppose that \(A, B\) , and \(C\) are vertices of a triangle and that \(a, b,\) and \(c\) are, respectively, the midpoints of the opposite sides. Show that \(\o
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Use a CAS to plot the surfaces in Exercises \(53-58 .\) Identify the type of quadric surface from your graph. $$\frac{y^{2}}{16}=1-\frac{x^{2}}{9}+z$$
View solution Problem 56
Find the centers and radii of the spheres in Exercises \(55-58 .\) $$x^{2}+y^{2}+z^{2}-6 y+8 z=0$$
View solution