Problem 56
Question
In \(46-60,\) write each quotient in \(a+b i\) form. $$ \frac{8+6 i}{2 i} $$
Step-by-Step Solution
Verified Answer
The quotient in \(a + bi\) form is \(3 - 4i\).
1Step 1: Write the Expression
The problem asks you to find the expression in the form \(a + bi\) for the complex number quotient \(\frac{8+6i}{2i}\). That means it needs to be rewritten from a fraction into a standard complex number format.
2Step 2: Multiply by the Conjugate
To eliminate the imaginary number from the denominator, multiply both the numerator and the denominator by the conjugate of the denominator. For \(2i\), the conjugate is \(-2i\). So, multiply \(\frac{8+6i}{2i}\) by \(\frac{-2i}{-2i}\).\[\left( \frac{8+6i}{2i} \right) \cdot \left( \frac{-2i}{-2i} \right) = \frac{(8+6i)(-2i)}{(2i)(-2i)}\]
3Step 3: Simplify the Denominator
Calculate the denominator part: \((2i)(-2i) = -4i^2\). Using \(i^2 = -1\), we have:\[-4i^2 = -4(-1) = 4\].Thus, the denominator simplifies to 4.
4Step 4: Simplify the Numerator
Expand the numerator using the distributive property: \[(8+6i)(-2i) = 8(-2i) + 6i(-2i)\]Calculate each term: \[8(-2i) = -16i\]\[6i(-2i) = -12i^2 = -12(-1) = 12\]Combine them: \[12 - 16i\].
5Step 5: Combine and Simplify
Combine the results from the previous steps and write the expression in the form \(a + bi\):\[\frac{12 - 16i}{4} = \frac{12}{4} - \frac{16i}{4} = 3 - 4i\].
Key Concepts
Imaginary UnitComplex ConjugateStandard Form of Complex NumbersDistributive Property
Imaginary Unit
In mathematics, the imaginary unit is denoted by the symbol \(i\). This symbol represents the square root of -1. In other words, \(i^2 = -1\). It's a fundamental component in the realm of complex numbers and allows for the extension of the real number system.
- Understanding \(i^2\): Given that the square of \(i\) is -1, this provides a foundation for many operations with complex numbers.
- Solving equations: Imaginary units enable solutions to equations that have no real solutions, such as subtraction under square roots (e.g., \(\sqrt{-4}\)).
Complex Conjugate
The complex conjugate of a complex number is a useful concept that can help in simplifying expressions, especially when dividing complex numbers. Consider a complex number of the form \(a + bi\), its conjugate is \(a - bi\).
- Formation: To find the conjugate, simply change the sign of the imaginary part.
- Properties: Multiplying a complex number by its conjugate results in a real number. For instance, \((a + bi)(a - bi) = a^2 + b^2\).
Standard Form of Complex Numbers
The standard form for writing complex numbers is \(a + bi\), where \(a\) and \(b\) are real numbers. Here, \(a\) is known as the real part, while \(bi\) is the imaginary part.
- Real part: The component \(a\) represents the real number space in a complex number.
- Imaginary part: The component \(bi\) extends the real number into a complex plane.
Distributive Property
The distributive property is a basic algebraic property that plays an important role when working with complex numbers. It states that for all numbers \(a\), \(b\), and \(c\), the expression \(a(b + c) = ab + ac\) holds true.
- Application: This property is key when multiplying a complex number by another number, as it involves distributing the multiplication over addition.
- Expanding expressions: In the exercise, the distributive property was used to handle \((8+6i)(-2i)\) effectively, breaking it into two simpler parts.
Other exercises in this chapter
Problem 55
In \(46-60,\) write each quotient in \(a+b i\) form. $$ \frac{12+3 i}{3 i} $$
View solution Problem 56
a. On the same set of axes, sketch the graphs of \(y=x^{2}-4 x+5\) and \(y=2 x+2\) b. Does the system of equations \(y=x^{2}-4 x+5\) and \(y=2 x+2\) have a comm
View solution Problem 57
a. On the same set of axes, sketch the graphs of \(y=x^{2}+5\) and \(y=2 x\) b. Does the system of equations \(y=x^{2}+5\) and \(y=2 x\) have a common solution
View solution Problem 57
In \(46-60,\) write each quotient in \(a+b i\) form. $$ \frac{\frac{1}{5}-\frac{1}{5} i}{\frac{5}{3}-4 i} $$
View solution